我是Mysql查询的新手。
我有2个表(tbl1,tbl2)
我需要以start_time升序加入两个表并过滤日期和emp_id
此处表格字段不同(开始时间 - >及时,结束时间 - >退出时间)
tbl-1:
id start-time end-time date emp_id
1 09:00:00 09:00:59 2014-05-14 1
2 10:00:00 10:00:59 2014-05-14 1
3 12:00:00 12:00:59 2014-05-14 1
4 14:00:00 14:00:59 2014-05-14 1
5 16:00:00 17:00:59 2014-05-13 1
tbl-2:
id in-time out-time date emp_id
1 11:00:00 11:00:59 2014-05-14 1
2 13:00:00 13:00:59 2014-05-14 1
3 15:00:00 15:00:59 2014-05-14 1
4 18:00:00 19:00:59 2014-05-14 2
5 20:00:00 20:00:59 2014-05-15 1
filterd by date, emp_id ordered by date
result-tbl:
id start-time end-time date emp_id
1 09:00:00 09:00:59 2014-05-14 1
2 10:00:00 10:00:59 2014-05-14 1
3 11:00:00 11:00:59 2014-05-14 1
4 12:00:00 12:00:59 2014-05-14 1
5 13:00:00 13:00:59 2014-05-14 1
6 14:00:00 14:00:59 2014-05-14 1
7 15:00:00 15:00:59 2014-05-14 1
答案 0 :(得分:1)
我不认为你想加入。我想你想要一个union all
以及一个重新分配id
的方法。类似的东西:
select (@rn := @rn + 1) as id, intime as starttime, outtime as outtime, emp_id
from ((select * from tbl1)
union all
(select * from tbl2)
) t cross join
(select @rn := 0) var
where emp_id = 1 and
intime <= '18:00:00'
order by intime;
答案 1 :(得分:0)
你想要一个记录联盟吗?
select in_time, out_time, date, emp_id from tbl1
union all
select star_time, end_time, date, emp_id from tbl2
order by in_time, out_time, date, emp_id;
编辑:加上过滤器:
select in_time, out_time, date, emp_id from tbl1
where emp_id = 1 and date = '2014-05-14'
union all
select star_time, end_time, date, emp_id from tbl2
where emp_id = 1 and date = '2014-05-14'
order by in_time, out_time;
答案 2 :(得分:0)
这可能会解决您的问题。
select *
from (
select id,star_time,end_time,date,emp_id
from tbl1
where [date-filter-condition]
union all
select id,in_time as star_time,out_time end_time,date,emp_id
from tbl2
where [date-filter-condition]
) tmp
where tmp.date==[some-date-filter] and tmp.emp_id=[some-emp-id-filter]
order by tmp.date