Question

现在我有了这个

ByteArrayInputStream in = new ByteArrayInputStream("2".getBytes());
System.setIn(in);

//code that does something with user inputs

但问题是，在//代码执行的操作中，我有多个用户输入提示，是否可以形成用户输入列表并在时机到来时获取相应的输入？我尝试过像＃34; 2 \ n2 \ n10 \ nHello \ n＆＃34; .getBytes（）这样的愚蠢的事情，但这并没有奏效。

编辑：

我通过Scanner对象获取用户输入：

Scanner inputScanner = new Scanner(System.in);
inputScanner.nextLine();

Answer 1

你可以这样做：

使用模拟输入和延迟时间构建DelayQueue。
在调用read（）时，扩展BytArrayInputStream并覆盖read()方法以读取DelayQueue。

编辑：示例代码（未完全实施 - 我在电话会议上）

public class DelayedString implements Delayed {

    private final long delayInMillis;

    private final String content;

    public DelayedString(long delay, String content) {
        this.delayInMillis = delay;
        this.content = content;
    }

    public String getContent() {
        return content;
    }

    public long getDelay(TimeUnit timeUnit) {
        return TimeUnit.MILLISECONDS.convert(delayInMillis, timeUnit);
    }
}

public class MyInputStream implements InputStream {

    private ByteBuffer buffer = ByteBuffer.allocate(8192);

    private final DelayQueue<DelayString> queue;

    public MyInputStream(DelayQueue<DelayString> queue) {
        this.queue = queue;
    }

     public int read() {
         updateBuffer();
         if (!buffer.isEmpty()) {
            // deliver content inside buffer
         }
     }

     public int read(char[] buffer, int count) {
         updateBuffer();
         // deliver content in byte buffer into buffer
     }

     protected void updateBuffer() {
         for (DelayedString s = queue.peek(); s != null; ) {
             if (buffer.capacity() > buffer.limit() + s.getContent（）.length()) {
                 s = queue.poll();
                 buffer.append(s.getContent());
             } else {
                 break;
             }
         }
     }
}

Answer 2

只需使用“新行”即可。

String simulatedUserInput = "input1" + System.getProperty("line.separator")
    + "input2" + System.getProperty("line.separator");

InputStream savedStandardInputStream = System.in;
System.setIn(new ByteArrayInputStream(simulatedUserInput.getBytes()));

// code that needs multiple user inputs

System.setIn(savedStandardInputStream);

如何为JUnit模拟多个用户输入

2 个答案: