我创建了一个口袋妖怪猜测应用程序,它在左侧显示一个神奇宝贝轮廓的图像,在右侧显示一个黑色矩形。如果用户无法正确猜出口袋妖怪,他/她可以按下显示口袋妖怪图片和名称的按钮。 首次启动applet时,它看起来像这样:http://i.imgur.com/2IO7kb3.png
当用户第一次点击“显示”时,它看起来像这样:http://i.imgur.com/xbTJzrF.png
当再次按下“随机口袋妖怪”时,它看起来像第二张图片,左边是口袋妖怪剪影,右边是透露图片。
我需要它,以便当用户再次按下“随机口袋妖怪”按钮时,它会再次显示黑色矩形。
import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.applet.*;
import java.util.Random;
public class giffs extends Applet implements ActionListener
{
boolean b = true;
AudioClip music0;
Random r = new Random(); // random number generator
int min = 1;
int max = 70;
int randomNumber = r.nextInt(max - min + 1) + min;
Button randompoke; // button to display a random pokemon
Button reveal; // reveals pokemon name
Image poke; // shaded out pokemon picture
Image poker; // revealed pokemon picture
Image pokeball;
public void init()
{
setSize(700,700);
music0 = getAudioClip(getDocumentBase(), "music2.au");
randompoke = new Button("Random Pokemon");
reveal = new Button("Reveal");
add(randompoke);
add(reveal);
randompoke.addActionListener(this);
reveal.addActionListener(this);
poke = getImage(getDocumentBase(), "poke" + randomNumber + ".PNG");
poker = getImage(getDocumentBase(), "poke" + randomNumber +"r"+ ".PNG");
pokeball = getImage(getDocumentBase(), "pokeball.gif");
music0.play();
}
public void update(Graphics g)
{
g.drawImage(poke,20,20,this);
g.drawImage(pokeball,450,20,this);
g.fillRect(650,20,450,640);
if (b == false)
{
g.drawImage(poker,650,20,this);
}
}
public void actionPerformed(ActionEvent evt)
{
if(evt.getSource()== randompoke)
{
Random r = new Random();
int randomNumber = r.nextInt(max - min + 1) + min;
poke = getImage(getDocumentBase(), "poke" + randomNumber + ".PNG");
poker = getImage(getDocumentBase(), "poke" + randomNumber +"r"+ ".PNG");
repaint();
}
else if(evt.getSource() == reveal)
{
b = false;
repaint();
}
}
}
答案 0 :(得分:1)
只需添加一个drawrectangle到
if(evt.getSource()== randompoke)
在actionperfomred内部。