Question

如何禁用PHP脚本中的舍入。如果我总结一下它只显示圆形数字。

<?php

$con=mysqli_connect("localhost","XXXX","XXXX","XXXX");
if (mysqli_connect_errno()) {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM energrid WHERE ID = 1 ");

while($row = mysqli_fetch_array($result)) {
    $wert = $row['Wert'];
}
$result = mysqli_query($con,"SELECT * FROM energrid WHERE ID = 3 ");

while($row = mysqli_fetch_array($result)) {
    $wert1 = $row['Wert'];
}
mysqli_close($con);
echo "here we go.:";
echo $wert + $wert1;
?>

好吧，我猜我发现了自己的错误。这些值与3,5相似，而不是a。

如果这些是直接来自MySQL DB的值，我怎么能改变呢？

Answer 1

像这样使用str_replace()以小数点,替换逗号.

$a = "3,5";

str_replace(",",".",$a);

Answer 2

1.您可以使用number_format功能
2. 优化您的代码 - 没有必要使用while循环来执行此操作

 <?php    
$db = mysql_connect("localhost","username","password");  ///connect to mysql      
if (!$db) {      
// throw error if not connect      
 die("Database connection failed miserably: " . mysql_error());      
        }          
$db_select = mysql_select_db("databasename",$db); ///select database      
if (!$db_select) {      
//database connection error      
die("Database selection also failed miserably: " . mysql_error());       
}      
$sum=0;       
$result = mysqli_query($db,"SELECT sum(wert) as sum FROM energrid WHERE ID in ('1','3') ");       
$row = mysqli_fetch_array($result)       
$sum =$row['sum'];       
`enter code here`      

echo number_format($sum,'number','.','');
//where number-no. of  place you want to round off 
?>

Answer 3

尝试使用这样的演员：

echo (int)$wert + (int)$wert1;
echo (float)$wert + (float)$wert1;

PHP禁用round_up

3 个答案: