对于我的项目dijon,我想知道是否可以将Scala pickling用于JSON serialization和deserialization。
具体来说,我想要这样的def toJsonString(json: JSON, prettyPrint: Boolean = false): String
和def fromJsonString(json: String): JSON
。如何使用酸洗来创建这两种辅助方法?
答案 0 :(得分:7)
这实际上取决于您最方便使用的方法。这些是您所选择的粗略草图:
import scala.pickling._, json._
// Uses macros implicitly on Scope
def toJSONString[A](obj: A, prettyPrint: Boolean = false)(implicit pickler: A => JSONPickle) = {
val json = pickler(obj)
myPrettyPrinter.print(json.value, prettyPrint)
}
// Uses macros defined elsewhere
def toJSONString(obj: Any, prettyPrint: Boolean = false) = {
val json = classToPicklerMap(obj.getClass)(obj)
myPrettyPrinter.print(json.value, prettyPrint)
}
// Uses runtime reflection
def toJSONString(obj: Any, prettyPrint: Boolean = false) = {
val json = obj.pickle
myPrettyPrinter.print(json.value, prettyPrint)
}
// Uses macros implicitly on scope
def fromJSONString[A](json: String)(implicit unpickler: JSONPickle => A): A = {
unpickler(JSONPickle(json))
}
// Uses macros defined elsewhere #1
def fromJSONString[A](json: String)(implicit c: ClassTag[A]) = {
classnameToUnpicklerMap(c.runtimeClass.getName)(json).asInstanceOf[A]
}
// Uses macros defined elsewhere #2
def fromJSONString(json: String): Any = {
val className = parseClassName(json) // Class name is stored in "tpe" field in the JSON
classnameToUnpicklerMap(className)(json)
}
// Uses runtime reflection
def fromJSONString(json: String) = JSONPickler(json).unpickle
答案 1 :(得分:0)
我还没有使用Scala Pickling,但它在其Github回购中表示它处于早期开发阶段。您可能还想试用Spray JSON。它也支持你需要的东西。