Question

我的问题是我的xml文件中有一个max 3出现的电子邮件元素，如下所示：

<contact> 
<email>A</email> 
<email>B</email> 
<email>C</email> 
</contact>

当我尝试使用以下代码编辑3个标签时，

xnl[0]["email"].InnerText = "D"; 
xnl[0]["email"].InnerText = "E"; 
xnl[0]["email"].InnerText = "F";

只编辑了第一封电子邮件，因为相同的xml元素名称存在覆盖问题。

<contact> 
<email>F</email> 
<email>B</email> 
<email>C</email> 
</contact>

我尝试xnl[0]["email"][0].InnerText = "D";选择第一个电子邮件元素名称，但这不起作用。有什么建议吗？

更新:(带代码）

c＃code：

        public String updateContact(Int32 getPhoneNumber, Int32 getWorkNumber, Int32 getMobileNumber, String photo, String firstName, String lastName, String gender, String dateOfBirth, Int32 home, Int32 work, Int32 mobile, String email1, String email2, String email3)
    {
        XmlDocument doc = new XmlDocument();
        doc.Load("xmlFile/xml/myContactBook/src/myContactBook.xml");

        XmlNodeList xnl = doc.SelectNodes("/contactBook/contact/phone[home='" + getPhoneNumber + "']/parent::* | /contactBook/contact/phone[work='" + getWorkNumber + "']/parent::* | /contactBook/contact/phone[mobile='" + getMobileNumber + "']/parent::* ");

        if (xnl.Count != 0)
        {
            xnl[0]["photo"].InnerText = photo;
            xnl[0]["firstName"].InnerText = firstName;
            xnl[0]["lastName"].InnerText = lastName;
            xnl[0]["gender"].InnerText = gender;
            xnl[0]["dateOfBirth"].InnerText = dateOfBirth;
            xnl[0]["phone"]["home"].InnerText = home.ToString();
            xnl[0]["phone"]["work"].InnerText = work.ToString();
            xnl[0]["phone"]["mobile"].InnerText = mobile.ToString();
            xnl[0]["email"].InnerText = email1;
            xnl[0]["email"].InnerText = email2;
            xnl[0]["email"].InnerText = email3;

        }

        doc.Save("xmlFile/xml/myContactBook/src/myContactBook.xml");

        return "Updated";
    }

xml代码：

<contact>
<photo>profilepic/default.jpg</photo>
<firstName>Hender</firstName>
<lastName>Casio</lastName>
<gender>Female</gender>
<dateOfBirth>1985-04-23</dateOfBirth>
<phone>
  <home>4453278</home>
  <work>3451390</work>
  <mobile>54356635</mobile>
</phone>
<email>casio.hender@mail.com</email>
<email>heder@aol.com</email>
<email>hencasio@yahoo.com</email>
</contact>

Answer 1

<强>问题即使您从XPath查询中获得XmlNodeList中返回的多个联系人，您也只是更新第一个节点。

如果您确定XPath查询应该返回一个或没有联系人，那么您应该使用SelectSingleNode。

这是fiddle。

XmlDocument doc = new XmlDocument();
doc.Load("xmlFile/xml/myContactBook/src/myContactBook.xml");

XmlNode xn = doc.SelectSingleNode("/contactBook/contact/phone[home='" + getPhoneNumber + "']/parent::* | /contactBook/contact/phone[work='" + getWorkNumber + "']/parent::* | /contactBook/contact/phone[mobile='" + getMobileNumber + "']/parent::* ");

if (xn != null)
{
     xn["photo"].InnerText = photo;
     xn["firstName"].InnerText = firstName;
     xn["lastName"].InnerText = lastName;
     xn["gender"].InnerText = gender;
     xn["dateOfBirth"].InnerText = dateOfBirth;
     xn["phone"]["home"].InnerText = home.ToString();
     xn["phone"]["work"].InnerText = work.ToString();
     xn["phone"]["mobile"].InnerText = mobile.ToString();

     XmlNodeList xnl = xn.SelectNodes("email");
     xnl[0].InnerText = email1;
     xnl[1].InnerText = email2;
     xnl[2].InnerText = email3;
}

doc.Save("xmlFile/xml/myContactBook/src/myContactBook.xml");
return "Updated";

更新 :( 解决方案2 ）如果您的XPath查询返回了多个结果：

XmlDocument doc = new XmlDocument();
doc.Load("xmlFile/xml/myContactBook/src/myContactBook.xml");

XmlNodeList xnl = doc.SelectNodes("/contactBook/contact/phone[home='" + getPhoneNumber + "']/parent::* | /contactBook/contact/phone[work='" + getWorkNumber + "']/parent::* | /contactBook/contact/phone[mobile='" + getMobileNumber + "']/parent::* ");

foreach(XmlNode xn in xnl)
{
     xn["photo"].InnerText = photo;
     xn["firstName"].InnerText = firstName;
     xn["lastName"].InnerText = lastName;
     xn["gender"].InnerText = gender;
     xn["dateOfBirth"].InnerText = dateOfBirth;
     xn["phone"]["home"].InnerText = home.ToString();
     xn["phone"]["work"].InnerText = work.ToString();
     xn["phone"]["mobile"].InnerText = mobile.ToString();

     XmlNodeList xnlElement = xn.SelectNodes("email");
     xnlElement[0].InnerText = email1;
     xnlElement[1].InnerText = email2;
     xnlElement[2].InnerText = email3;
}

doc.Save("xmlFile/xml/myContactBook/src/myContactBook.xml");
return "Updated";

使用类似的标记（元素）名称更新xml innerText

1 个答案: