Question

查询

select 
    territory, new,
    rank() over (order by new ASC) as rank_1  
case 
when rank_1 <= (select count(new)/3 from ##final) then 'low'
when rank_1 <= (select (count(new)/3)*2 from ##final) then 'medium'
when rank_1 <= (select count(new) from ##final) then 'high'
else 'error'
end 
from 
    ##final 
order by 
    territory

表

territory       new
6310101     941
6310102     186
6310103         458
6310103     458
6310104     109
6310105     113
6310106     305
6310107     189
6310108     184
6310109     737
6310110     862
6310110     862
6310201     1079
6310202     236
6310203     1529

错误讯息：

Msg 156，Level 15，State 1，Line 3
  关键字＆＃39; case＆＃39;附近的语法不正确   Msg 156，Level 15，State 1，Line 4
  关键字＆＃39;然后＆＃39;附近的语法不正确   消息156，15级，状态1，行5   关键字＆＃39;然后＆＃39;附近的语法不正确   Msg 156，Level 15，State 1，Line 6
  关键字＆＃39;然后＆＃39;。
附近的语法不正确

Answer 1

您不能直接引用此列，需要子查询或CTE：

WITH CTE AS
(
   SELECT territory, new,
        RANK() Over (Order By new ASC) as rank_1  
   FROM ##final 
)
SELECT territory, new, 'error' =
       case 
           when rank_1 <= (select count(new)/3 from ##final) then 'low'
           when rank_1 <= (select count(new)/3 from ##final) then 'medium'
           when rank_1 <= (select count(new)/3 from ##final) then 'high'
       else 'error' end 
FROM CTE
ORDER BY territory

Demo

如何在SQL Server中使用大小写等级

1 个答案: