使用两个表中的条件从MySQL表中选择数据

Question

我有两个MySQL表HouseHold和UserProfile。两个表都包含HouseHoldID列。我想从HouseHold Table中选择两个表中HouseHoldID相等的所有行。我怎样才能做到这一点？我使用以下代码

select * from Household where Household.HouseholdID = UserProfile.HouseholdID

但它没有给出任何反映错误的东西。 任何人都可以帮助我吗？

Answer 1

你必须从两个表中选择
喜欢以下方式：

select * from Household, UserProfile where Household.HouseholdID = UserProfile.HouseholdID

或使用加入

select * from Household h
JOIN UserProfile u
ON u.HouseholdID=h.HouseholdID

Answer 2

您还需要选择UserProfile表

select * from Household h JOIN UserProfile u ON h.HouseholdID = u.HouseholdID

Answer 3

您可以尝试：

SELECT A.* FROM Household A INNER JOIN UserProfile B ON A.HouseholdID = B.HouseholdID

Answer 4

您可以使用JOIN：

select * from Household
JOIN UserProfile
ON UserProfile.HouseholdID=Household.HouseholdID

或使用EXISTS：

select * from Household
WHERE EXISTS
(
   SELECT NULL
   FROM UserProfile
   WHERE UserProfile.HouseholdID=Household.HouseholdID
)

或使用IN：

select * from Household
WHERE Household.HouseholdID IN 
(
   SELECT UserProfile.HouseholdID
   FROM UserProfile
)

或者使用from语句的旧方法

select * from Household, UserProfile
WHERE UserProfile.HouseholdID=Household.HouseholdID

这有点取决于您想要的数据

Answer 5

您需要JOIN表格。试试这个：

select * from 
Household h JOIN
UserProfile u ON u.HouseholdID =h.HouseholdID 

详细了解加入here。

Answer 6

那么，SQL语言有非常巧妙的方法可以按照给定的标准从两个表中选择记录，它被称为 JOIN ：

SELECT H.*, U.* FROM Household H 
INNER JOIN UserProfile U ON U.HouseholdID = H.HouseholdID