Question

我正在尝试使用我已经拥有的搜索小部件创建一个可搜索的列表（android：id =＆＃34; @ + id / searchView1＆＃34;），到目前为止，我只找到了有关使用ArrayAdapters的ListViews的帮助这些解决方案没有奏效

这是我的代码

public class SearchActivity extends Activity {
ListView listView ;
// Array of words: source http://www.knittinghelp.com/videos/knitting-glossary
String[] words = new String[] {
        "( )",
        "[ ]",
        "*",
        "**",
        "alt",
        "approx",
        "beg",
        "bet",
        "BO",
        "CA",
        "CB",
        "CC",
        "cdd",
        "ch",
        "cm",
        "cn",
        "CO",
        "cont"
};

// Array of meanings: source http://www.knittinghelp.com/videos/knitting-glossary
String[] meaning = new String[]{
    "work instruction between parentheses, in the place directed",
    "work instructions between brackets, as many times as directed",
    "repeat instructions following the single asterisk as directed",
    "repeat instructions between asterisks, as directed",
    "alternative",
    "approximately",
    "beginning",
    "between",
    "Bind off",
    "colour A",
    "colour B",
    "colour C",
    "centered double decrease. sl2 tog, K1, pass the slipped stitches over (together)",
    "chain (using crochet hook). Start with a slip knot.",
    "centimeter(s)",
    "cable needle: short knitting needle, used as an aid in the twisting of a cable.",
    "cast on",
    "continue"
};

/**
 * When the search activity begins, show the view as in the search xml, and list the
 * given values in the list view
 */
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_search);

    final List<HashMap<String, String>> wordList = new ArrayList<HashMap<String, String>>();        

    for(int i=0; i<words.length; i++){
        HashMap<String, String> hashMap = new HashMap<String, String>();
        hashMap.put("word", words[i]);
        hashMap.put("meaning", meaning[i]);           
        wordList.add(hashMap);        
    }        

    final SimpleAdapter adapter = new SimpleAdapter(this, wordList, 
            android.R.layout.simple_list_item_2, 
            new String[] {"word", "meaning"}, 
            new int[] {android.R.id.text1, android.R.id.text2});

    ListView listView = (ListView) findViewById(R.id.listView1);

    listView.setAdapter(adapter); 

    EditText search = (EditText) findViewById(R.id.searchView1);

    search.addTextChangedListener(new TextWatcher() {

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            // TODO Auto-generated method stub
             SearchActivity.this.adapter.getFilter().filter(s);

        }

        @Override
        public void beforeTextChanged(CharSequence s, int start, int count,
                int after) {
            // TODO Auto-generated method stub

        }

        @Override
        public void afterTextChanged(Editable s) {
            // TODO Auto-generated method stub

        }
    }); 
}
}

在onTextChanged中，我在适配器上遇到错误，说它无法解决。如果有人能指出我正确的方向，那将是非常棒的：）

Answer 1

您需要在外部类中添加一个名为adapter的实例变量。基于您发布的代码块，您需要有一个名为adapter的SimpleAdapter成员变量，如下所示：

public class SearchActivity extends Activity {
   ListView listView;
   SimpleAdapter adapter; // this is what you're missing

因为SearchActivity.this.adapter.getFilter().filter(s)正在引用一个名为适配器的实例变量，该实例变量属于SearchActivity类（当前不存在）。

搜索使用SimpleAdapter android的ListView

1 个答案: