Question

我是java opennlp的新手，我正在尝试实现一个从文件中提取城市名称的程序，但我首先在字符串上测试我的代码，然后出现一些错误代码是

 import java.io.FileInputStream;
 import java.io.FileNotFoundException;
 import java.io.IOException;
 import java.io.InputStream;

 import main.java.opennlp.tools.namefind.NameFinderME;
 import main.java.opennlp.tools.namefind.TokenNameFinderModel;
 import main.java.opennlp.tools.util.InvalidFormatException;
 import main.java.opennlp.tools.util.Span;
 import opennlp.tools.tokenize.Tokenizer;
 import opennlp.tools.tokenize.TokenizerME;
 import opennlp.tools.tokenize.TokenizerModel;
 import opennlp.tools.tokenize.SimpleTokenizer;
 import opennlp.tools.sentdetect.SentenceDetectorME;
 import opennlp.tools.sentdetect.SentenceModel;

  import org.xml.sax.SAXException;

 public class CityFinder {

public String Tokens[];

public static void main(String[] args) throws IOException, SAXException {

    CityFinder toi = new CityFinder();
    String cnt;
    cnt="John is planning to specialize in Electrical Engineering in UC Berkley and  pursue a career with IBM.";
    toi.tokenization(cnt);
    String cities = toi.namefind(toi.Tokens);
    String org = toi.orgfind(toi.Tokens);

    System.out.println("City name is : "+cities);
    System.out.println("organization name is: "+org);

}
    public String namefind(String cnt[]) {
    InputStream is;
    TokenNameFinderModel tnf;
    NameFinderME nf;
    String sd = "";
    try {
        is = new FileInputStream("en-ner-location.bin");
        tnf = new TokenNameFinderModel(is);
        nf = new NameFinderME(tnf);
        Span sp[] = nf.find(cnt);
        StringBuilder fd = new StringBuilder();
        int l = a.length;

        for (int j = 0; j < l; j++) {
            fd = fd.append(a[j] + "\n");

        }
        sd = fd.toString();

    } catch (FileNotFoundException e) {

        e.printStackTrace();
    } catch (InvalidFormatException e) {

        e.printStackTrace();
    } catch (IOException e) {

        e.printStackTrace();
    }
    return sd;
}

public String orgfind(String cnt[]) {
    InputStream is;
    TokenNameFinderModel tnf;
    NameFinderME nf;
    String sd = "";
    try {
        is = new FileInputStream("en-ner-organization.bin");
        tnf = new TokenNameFinderModel(is);
        nf = new NameFinderME(tnf);
        Span sp[] = nf.find(cnt);
        String a[] = Span.spansToStrings(sp, cnt);
        StringBuilder fd = new StringBuilder();
        int l = a.length;
        for (int j = 0; j < l; j++) {
            fd = fd.append(a[j] + "\n");

        }

        sd = fd.toString();

    } catch (FileNotFoundException e) {

        e.printStackTrace();
    } catch (InvalidFormatException e) {

        e.printStackTrace();
    } catch (IOException e) {

        e.printStackTrace();
    }
    return sd;

}
public void tokenization(String tokens) {

    InputStream is;
    TokenizerModel tm;
    try {
        is = new FileInputStream("en-token.bin");
        tm = new TokenizerModel(is);
        Tokenizer tz = new TokenizerME(tm);
        Tokens = tz.tokenize(tokens);
        // System.out.println(Tokens[1]);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

  }

以及我使用span verialble获得的错误 Span sp [] = nf.find（cnt）; 错误是类型不匹配：无法从opennlp.tools.util.Span []转换为main.java.opennlp.tools.util.Span [] 我不知道如何在两个地方解决这个问题

任何建议......？提前谢谢

Answer 1

您应该从opennlp.tools包中的包中导入所有类。

 import opennlp.tools.namefind.NameFinderME;
 import opennlp.tools.namefind.TokenNameFinderModel;
 import opennlp.tools.util.InvalidFormatException;
 import opennlp.tools.util.Span;

opennlp eclipse中的span类java

1 个答案: