Question

我希望以天/小时/分钟来计算两个日期之间的差异。

我有一个包含以下数据结构的表：

 ID                   Date                           Location          Type
---------------------------------------------------------------------------------
42ABC          15-NOV-14 12.45.00 PM                    YY            Departed 
42ABC          15-NOV-14 03.10.00 PM                    AA            Arrived
42ABC          18-NOV-14 05.15.00 PM                    AA            Departed
42ABC          18-NOV-14 07.20.00 PM                    YY            Arrived

我如何计算日期的差异，并得到类似的结果：

ID                Location                   DURATION
-----------------------------------------------------------------
42ABC               AA                 3 days, 2 hours, 5 minutes

感谢您对此的投入。

Answer 1

首先想到的解决方案是：

SELECT id,
       location,
          TRUNC (date_diff)
       || ' days, '
       || TRUNC ( (date_diff - TRUNC (date_diff)) * 24)
       || ' hours, '
       || MOD ( (date_diff - TRUNC (date_diff)) * 24, 10) * 60
       || ' minutes'
FROM   (SELECT   id, location, MAX (date) - MIN (date) AS date_diff
        FROM     your_table
        GROUP BY id, location)

当你在Oracle中减去两个日期时，结果是一个表示天数的十进制数，所以只需数学就可以得出小时和分钟。如果你想要这个更复杂（例如，如果数字为零则删除部分），那么我建议使用一个函数。

也可以使用稍微简单的解决方案，从date转换为timestamp，这会产生interval类型的结果，而不是decimal

interval解决方案：

SELECT id,
       location,
          EXTRACT (DAY FROM date_diff)
       || ' days, '
       || EXTRACT (HOUR FROM date_diff)
       || ' hours, '
       || EXTRACT (MINUTE FROM date_diff)
       || ' minutes'
FROM   (SELECT   id, location, 
                 CAST(MAX (date) as timestamp) 
                 - CAST(MIN (date) as timestamp) AS date_diff
        FROM     your_table
        GROUP BY id, location)

Answer 2

这没关系：

select T1.ID, T2.LOCATION, round(T2.DDATE - T1.DDATE) || ' days, ' ||
            trunc(mod((T2.DDATE - T1.DDATE)*24, 24)) || ' hours, ' ||
            trunc(mod((T2.DDATE - T1.DDATE)*24*60, 60)) || ' minutes' duration
from YOUR_TABLE T1, YOUR_TABLE T2
where T2.ID = T1.ID
  and T2.LOCATION = T1.LOCATION
  and T1.TYPE = 'Arrived'
  and T2.TYPE = 'Departed'
;

oracle中同一列中两个日期之间的差异，以天/小时/分钟为单位

2 个答案: