Question

我有一个SQL表，其中包含一些包含一些HTML / XML标记的列。这是一个例子：

<root><Physicians><name>John Helsinki, MD</name>
<picture><img src="/uploadedImages/svr/physicians/images/John web.jpg?n=9059" alt="Helsinki, John Photo" /></picture>
<gender>M</gender>
<specialty><a href="/WA/test.aspx?56" title="Eye Care">OPT</a></specialty>
<specialty2></specialty2>
<specialty3></specialty3>
<additional_specialty></additional_specialty>
</Physicians>
</root>

如何提取<img>之间的<picture></picture>标记？

我知道我可以在SQL中使用LIKE关键字，但我不确定如何继续...

Answer 1

您可以使用XPath利用列类型 - XML

declare @thing XML
set @thing = '<root><Physicians><name>John Helsinki, MD</name>
<picture><img src="/uploadedImages/svr/physicians/images/John web.jpg?n=9059" alt="Helsinki, John Photo" /></picture>
<gender>M</gender>
<specialty><a href="/WA/test.aspx?56" title="Eye Care">OPT</a></specialty>
<specialty2></specialty2>
<specialty3></specialty3>
<additional_specialty></additional_specialty>
</Physicians>
</root>'

SELECT @thing.query('/root/Physicians/picture/img')

通过表格的另一种方式：

DECLARE @XmlTable TABLE (ID INT NOT NULL, XmlData XML)
INSERT INTO @XmlTable 
        (ID, XmlData)
VALUES
        (1, '<root><Physicians><name>John Helsinki, MD</name>
<picture><img src="/uploadedImages/svr/physicians/images/John web.jpg?n=9059" alt="Helsinki, John Photo" /></picture>
<gender>M</gender>
<specialty><a href="/WA/test.aspx?56" title="Eye Care">OPT</a></specialty>
<specialty2></specialty2>
<specialty3></specialty3>
<additional_specialty></additional_specialty>
</Physicians>
</root>')

select XmlData.query('/root/Physicians/picture/img') from @XmlTable

这利用了任何XML变量类型上可用的query method，因此在此上下文中：

select [column].query('/root/Physicians/picture/img') from [table]

如何从列中检索HTML标记

1 个答案: