Question

当我进行练习时，我有一个问题是用C语言模拟CPU时间安排

我将CPU定义为类似

的结构

struct CPU 
{
    int state;      // state = 1 : CPU is FREE
            // state = 0 : CPU is BUSY 
}

用户输入他们想要用于时间安排的CPU数量（我称之为CPU_number）

问题是如何创建CPU.CPU1，CPU.CPU2，...等于CPU_Number

有谁知道怎么做？

Answer 1

你需要一个数组

struct CPU {
    int state; // 0: BUSY, 1: FREE
};

struct CPU cpu[10];

cpu[0].state = 1;                          // set cpu[0] as free
for (k = 1; k < 10; k++) cpu[k].state = 0; // set others as busy

Answer 2

这是一个名为＆＃34; CPU＆＃34;的结构类型的定义，而不是一个名为＆＃34; CPU＆＃34;的特定实例。在进行任何操作之前，您需要创建该结构的实例：

struct CPU cpu1, cpu2; // through cpuN;
cpu1.state = 0; //etc

Answer 3

这应该让你输入一个数字和malloc所需的结构

int iEach;
int CPU_number;
struct CPU {
    int state;
} *pcpu;

printf ( "enter number of CPU's: ");
scanf( "%d", &CPU_number);
pcpu = malloc ( sizeof (struct CPU) * CPU_number);
for ( iEach = 0; iEach < CPU_number; iEach++) {
    // here are equivalent ways to access the structures
    pcpu[iEach].state = 1;
    (pcpu + iEach)->state = 1;
}
free ( pcpu); // remember to free memory when you are done

创建大量与C中用户输入的数字相等的数据

3 个答案: