Question

考虑两个日期之间有44天。我想要的结果是2个月而不是1个月或1个月14天。我在php和mysql中尝试了几个日期函数，但未能获得确切的结果。我也尝试了自己的（下面）代码。

 $dt1 = some date
        $dt2 = some date

    $date1 = date_create("".$dtl."");

    $date2 = date_create("".$dt2."");

    $dateDiff = date_diff($date2, $date1);

    $probDays = $dateDiff->days;
    $probMon =  $dateDiff->m;
    $probYear = $dateDiff->y;

    $month = $probDays / 30;
    $totLeave = $month * 1;

   if($month > $probmon)
   { 
    $totLeave = $totLeave + 1;
   }

但我失败了。代码是关于为客户添加休假日。在php或mysql中的任何解决方案都会感激不尽。谢谢所有志愿者。

Answer 1

尝试检查天数，如果不等于零，则添加1到月计数并返回该月值。

Answer 2

使用PHP 5.3，也许您可以尝试以下方法：

<?php
$dt1 = "2014-05-12";
$dt2 = "2014-06-15";
$date1 = new DateTime($dt1);
$date2 = new DateTime($dt2);
$months = $date1->diff($date2)->m;
$days = $date1->diff($date2)->d;
if ($days >= 1) $months++;
echo $months." months!";
?>

Answer 3

<?php
$dt_dif= $dt2 - $dt1 ;

$y = $tot_exp / 365;
$d = $tot_exp % 365;
$m = $d / 30;

$year = (int)$y;
$month = (int)$m;
$day= (int)$d;

$total="".$month."month(s) ".$day."day(s)";
?>

Answer 4

John Riedel的答案是正确答案！

您需要使用$ start_date-＆gt; diff（$ end_date） - ＆gt; m＆amp; $ start_date-＆gt; diff（$ end_date） - ＆gt; d找出月份＆amp;日期差异..如果天数大于0，那么您需要增加此处所述的月数......

http://www.phpguy.in/finding-difference-between-2-dates-in-php/

Answer 5

    $date_from = "2011-01-22";
    $date_to = "2011-03-23";
    $date_from = date('Y-m-d', strtotime($date_from));
    $date_to = date('Y-m-d', strtotime($date_to));
    $y1 = date('Y', strtotime($date_from));
    $y2 = date('Y', strtotime($date_to));
    $m1 = date('m', strtotime($date_from));
    $m2 = date('m', strtotime($date_to));
    $day1 = date('d', strtotime($date_from));
    $day2 = date('d', strtotime($date_to));
    $yearDiff = $y2 - $y1;
    if ($m2 > $m1) {
        $month = $m2 - $m1;
    } else {
        $month = 0;
    }

    if ($yearDiff > 0 && $m1 > $m2) {
        $yearMonth = (($yearDiff * 12) - ($m1 - $m2));
    } else {
        $yearMonth = $yearDiff * 12;
    }

    if ($day1 > $day2) {
        $month = ($month - 1);
    }
    $total_month = $yearMonth + $month;
    $total_month = ($total_month > 1) ? $total_month . " months" : $total_month . " month";
    echo "Total " . $total_month;

如何计算两个日期之间的确切月份

5 个答案: