我有这个HTML代码,我想搜索一年和一学期:
<script>
function aa() {
xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","rankGradePrint.php?nm="+document.form1.t1.value,false);
xmlhttp.send(null);
document.getElementById("d1").innerHTML=xmlhttp.responseText;
}
function bb() {
xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","rankGradePrint.php?nmm="+document.form2.t2.value,false);
xmlhttp.send(null);
document.getElementById("d1").innerHTML=xmlhttp.responseText;
}
</script>
<form name="form1" method="post">
<table width="405px" align="center">
<tr>
<td width="5%"><img src="imgs/icSearch.png" height="25"/></td>
<td><input type="text" name="t1" OnKeyup="aa();" class="box3" placeholder="Year"> </td>
</tr>
</table>
</form>
<form name="form2" method="post">
<table width="405px" align="center">
<tr>
<td width="5%"><img src="imgs/icSearch.png" height="25"/></td>
<td><input type="text" name="t2" OnKeyup="bb();" class="box3" placeholder="Semester"></td>
</tr>
</table>
这是我的rankGradePrint.php
<?php $nm1=$_GET['nm'];
$nm2=$_GET['nmm'];
if (empty($nm1)){
echo " ";
exit;
}
if (empty($nm2)){
echo " ";
exit;
}
include('konek.php');
$query1="SELECT t2.schoUsername, t2.schoSurname, t2.schoFirstname, t2.schoMiddlename, t1.gradeAve, t1.gradeSem, t1.gradeSender
FROM tblgrade AS t1 JOIN tblscholar AS t2
ON t1.gradeSender=t2.schoUsername
WHERE t1.gYear LIKE ('$nm1%') AND t1.gradeSem LIKE ('$nm2%')
GROUP BY t1.gradeSender ";
$result = mysql_query($query1) or die(mysql_error());
while($row=mysql_fetch_array($result))
{
echo $row['gradeSem'];
echo " - ";
echo $row['schoSurname'] . ", ". $row['schoFirstname'] . " ". $row['schoMiddlename'];
if($row['gradeAve']<='2.5'){
echo '<h1 style="text-decoration:none; color: #f60b3c;"><strong>'. $row['gradeAve'] .'</strong></h1>';
}
else{
echo '<h1 style="text-decoration:none; color: #000510;><strong>'. $row['gradeAve'] .'</strong>';
}
}
?>
<div id="d1"></div>
我的问题是,当我输入文本框时,没有结果。我不知道是什么问题。我的查询中有问题吗?或者在我的文件中?
答案 0 :(得分:0)
您的should请求异步,但是您无法使用以下内容:
document.getElementById("d1").innerHTML=xmlhttp.responseText;
相反,您必须指定回调:
xmlhttp.onload = function() {
document.getElementById("d1").innerHTML = this.responseText;
};
我建议使用POST
进行搜索:
xmlhttp=new XMLHttpRequest();
xmlhttp.open("POST", "/path/to/your/script.php", true);
xmlhttp.onload = function() {
alert(this.responseText);
};
data = new FormData();
data.append('nm', your_value);
xmlhttp.send(data); // could be a form dom node instead
请参阅MDN reference。
我还创建了一个jsFiddle来演示它。
此外,由于itachi已经mentioned in the comments,您应该使用MySQLi或PDO而不是已弃用的mysql_*
函数。