Question

我正在使用Oracle，PL / SQL。我写了以下程序：

Declare result number;
       countExceed Number;
begin
select count(*) into result from 
    (select "LoginName","LoginPassword" from "ApplicationUser" where "LoginName"='adin' and "LoginPassword"='admin');
if result>0
then
execute immediate('Update "test" set "Count"=0 where "Count"<5');
dbms_output.put_line('Update as count 0!');
elsif result=0 then
execute immediate(' select "Count"
                    into countExceed from "test";
                    if countExceed >5 then 
                Update "test" set "Count"="Count"+1 where "Count" <5;
                    END IF;');
dbms_output.put_line('Update as Count + 1!');
End If;
end;

我想要做的就是：

检查用户名和密码，如果存在则检查计数＆lt; = 5，如果真实更新计数= 0，则其中username =＆＃39; admin＆＃39;。如果存在用户名和密码，并且如果count> 5，则更新Isactive = 0。最后如果用户名和密码不存在，则更新count = count + 1，其中username = username。

上述程序给我这个错误

ORA-00911：无效字符请帮助。

Answer 1

试试这个

Declare result number;
       countExceed Number;
begin
  select count(*) into result from ApplicationUser where LoginName='adin' and LoginPassword='admin';
  if result>0 then
    execute immediate('Update "test" set "Count"=0 where "Count"<5');
    dbms_output.put_line('Update as count 0!');
  else
      select "Count" into countExceed from "test";
      if countExceed >5 then 
        execute immediate('Update "test" set "Count"="Count"+1 where "Count" <5');
    END IF;
    dbms_output.put_line('Update as Count + 1!');
  End If;
end;

if else条件在oracle中有更新和计数器

1 个答案: