Question

我想垂直打印以下列表字典：

result = {'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 1792.367554], 'Job': 'Desktop', 'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 1.0], 'Task': 'test', 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 2.060041]}

所以看起来应该是这样的：

Job           Task          LoadLevel         Blocks          Failure         WeightedLevel
Desktop       test          4546543           4384284         0,46544564      0,1354385
                            474454            978456          2               9655
                            9655              55654           966             665

等...

我尝试了一些我在网上找到的代码，但他们仍然会横向打印结果：

for k, d in result.items():
    print(k + ":", d)

和

print("\t".join(str(x) for x in result))

Answer 1

漂亮的打印表需要大量的代码（table-recipe，pretty-table）。在特定的基础上编写这种代码并不好玩;你不妨使用精心设计的模块。

如果你有pandas，你可以将dict直接转储到DataFrame中，并按照以下方式打印：

In [4]: import pandas as pd
In [5]: result = {'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 1792.367554], 'Job': 'Desktop', 'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 1.0], 'Task': 'test', 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 2.060041]}

In [6]: pd.DataFrame(result)
Out[6]: 
        Blocks  Failure      Job  LoadLevel  Task  WeightedLevel
0  7255.151855        2  Desktop   0.212399  test     388.850952
1   231.589661        2  Desktop   0.393191  test     716.718689
2     9.365415        2  Desktop   0.727874  test    1312.559570
3     0.553640        2  Desktop   1.347436  test    2405.087158
4     0.050400        2  Desktop   2.494368  test    4460.083984
5     0.006408        2  Desktop   4.617561  test    8543.792969
6     0.001204        2  Desktop   8.548006  test   18805.201172
7     0.000842        2  Desktop  15.824027  test   57438.140625
8     2.060041        2  Desktop   1.000000  test    1792.367554

[9 rows x 6 columns]

这是一种在不使用第三方模块的情况下以类似表格式打印字典的方法：

import itertools as IT

result = {'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 1792.367554], 'Job': 'Desktop', 'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 1.0], 'Task': 'test', 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 2.060041]}

matrix = zip(*[value if isinstance(value, list) else IT.repeat(value) for key,value in result.items()])
print(''.join(['{:15}'.format(key) for key in result.keys()]))
for row in matrix:
    print(''.join(['{:15}'.format(str(item)) for item in row]))

产量

Task           Blocks         LoadLevel      Failure        Job            WeightedLevel  
test           7255.151855    0.212399       2.0            Desktop        388.850952     
test           231.589661     0.393191       2.0            Desktop        716.718689     
test           9.365415       0.727874       2.0            Desktop        1312.55957     
test           0.55364        1.347436       2.0            Desktop        2405.087158    
test           0.0504         2.494368       2.0            Desktop        4460.083984    
test           0.006408       4.617561       2.0            Desktop        8543.792969    
test           0.001204       8.548006       2.0            Desktop        18805.201172   
test           0.000842       15.824027      2.0            Desktop        57438.140625   
test           2.060041       1.0            2.0            Desktop        1792.367554

Answer 2

如果它们的长度相同，那么这很容易。你想要做的是将字典分开，然后在print语句中使用end kwarg循环打印。

如下所示。如果你使每个项目都是一个相同长度的列表，那就更容易了。

def print_dict_table(result):
    """Print a dictionary of lists like a table.

    Args:
        result (dict): Dictionary of lists to print as a table.
    """
    # Count the longest value
    keys = result.keys()
    count = 0
    for i in result.values():
        if isinstance(i, list) and len(i) > count:
            count = len(i)

    # print header
    for i in keys:
        print(i, end="\t")
    print()

    # print columns
    for i in range(count):
        for j in keys:
            if isinstance(result[j], list) and len(result[j]) >= i:
                    print(result[j][i], end="\t")
            else:
                print(result[j], end="\t")
        print()
# end print_dict_table


result = {'WeightedLevel': [388.850952, 716.718689, 1312.55957, 2405.087158, 4460.083984, 8543.792969, 18805.201172, 57438.140625, 1792.367554], 'Job': 'Desktop', 'LoadLevel': [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027, 1.0], 'Task': 'test', 'Failure': [2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0, 2.0], 'Blocks': [7255.151855, 231.589661, 9.365415, 0.55364, 0.0504, 0.006408, 0.001204, 0.000842, 2.060041]}

print_dict_table(result)

结果

Failure Job LoadLevel   WeightedLevel   Task    Blocks  
2.0 Desktop 0.212399    388.850952  test    7255.151855 
2.0 Desktop 0.393191    716.718689  test    231.589661  
2.0 Desktop 0.727874    1312.55957  test    9.365415    
2.0 Desktop 1.347436    2405.087158 test    0.55364 
2.0 Desktop 2.494368    4460.083984 test    0.0504  
2.0 Desktop 4.617561    8543.792969 test    0.006408    
2.0 Desktop 8.548006    18805.201172    test    0.001204    
2.0 Desktop 15.824027   57438.140625    test    0.000842    
2.0 Desktop 1.0 1792.367554 test    2.060041

不订购字典。老实说，我会重新定义您的数据结构。如果是表格数据则使用表格。

垂直打印列表字典

2 个答案: