Question

嘿所有我使用总和iff根据多个标准返回计数。

我基本上运行一个关于每个站点收到的呼叫的报告，但是我需要在结果集中包含0个呼叫的站点，如果他们没有那个星期的呼叫，则值为0或甚至为Null。

唯一的问题是我的cluase只包括本周有电话的网站

任何想法。

代码：

SELECT 
 d.sitename,
 count(c.Chargeablecalls) AS All_Calls,
 SUM(IIf(c.ChargeableCalls Like "Chargeable",1,0)) AS Chargeable_calls,
 d.sitetype

FROM
    (Callstatus AS s LEFT JOIN statusconversion AS c ON s.description=c.reportheading)             
INNER JOIN sitedetails AS d ON s.zone=d.zone

WHERE s.date_loaded BETWEEN 
(SELECT reportdate FROM reportMonth) AND (SELECT priorweek FROM reportMonth)
GROUP BY d.sitename, d.sitetype;

Answer 1

RIGHT JOIN需要sitedetails才能获得所有网站，即使是那些没有通话的网站。

您可能需要单独执行查询的前半部分，然后在主查询中使用该查询。

Answer 2

create a new query - qryCallStatus:

SELECT DISTINCT zone, description
FROM Callstatus, reportMonth
WHERE
Callstatus.date_loaded BETWEEN reportMonth.reportdate AND reportMonth.priorweek;

Then change your output query to:

SELECT 
 d.sitename,
 count(c.Chargeablecalls) AS All_Calls,
 SUM(IIf(c.ChargeableCalls Like "Chargeable",1,0)) AS Chargeable_calls,
 d.sitetype
FROM
    (sitedetails AS d LEFT JOIN qryCallStatus AS s ON d.zone=s.zone)             
LEFT JOIN statusconversion AS c ON s.description=c.reportheading
GROUP BY d.sitename, d.sitetype;

总和（IIF（包括0计数的结果）

2 个答案: