如何获取具有属性名称的xml标记

时间:2014-05-12 10:46:54

标签: php xml

我试图通过PHP simple_xml从字段“NMONTHLYINSTALMENT”获取值(编号21.48)。

这是我的PHP代码和XML:

$xml->data->struct("var[@name='NMONTHLYINSTALMENT']")->number

<wddxPacket version='1.0'><header/>
    <data>
      <struct>
        <var name='UWEBSHOPID'><string>6FF1633B-6AE0-4AB6-A19E-D934B7DF783F</string></var>
        <var name='NMONTHLYINSTALMENT'><number>21.48</number></var>
        <var name='CCOMMAND'><string>GetMonthlyInstalment</string></var>
        <var name='NDURATION'><string>48</string></var>
        <var name='NPRICE'><string>825.89</string></var>
        <var name='COUTPUTTYPE'><string>XML</string></var>
      </struct>
    </data>
</wddxPacket>

我无法上班!任何帮助都很受欢迎!谢谢!

2 个答案:

答案 0 :(得分:1)

<强> DEMO

您可以使用以下内容;

<?php

$xml_str = <<< EOT
<wddxPacket version='1.0'><header/>
    <data>
      <struct>
        <var name='UWEBSHOPID'><string>6FF1633B-6AE0-4AB6-A19E-D934B7DF783F</string></var>
        <var name='NMONTHLYINSTALMENT'><number>21.48</number></var>
        <var name='CCOMMAND'><string>GetMonthlyInstalment</string></var>
        <var name='NDURATION'><string>48</string></var>
        <var name='NPRICE'><string>825.89</string></var>
        <var name='COUTPUTTYPE'><string>XML</string></var>
      </struct>
    </data>
</wddxPacket>
EOT;

$xml = simplexml_load_string($xml_str);
$result = $xml->xpath('//data/struct/var[@name="NMONTHLYINSTALMENT"]/number');

echo $result[0][0];

答案 1 :(得分:0)

使用DomDocument和xml路径

$doc = new DomDocument;
$doc->Load("xmlfileName.xml");
$xpath = new DOMXPath($doc);
$path=$xpath->query("//data/struct/var[@name="NMONTHLYINSTALMENT"]/number")->item(0);
$doc->saveXML();