Question

我在随机化值方面存在问题。我想做的是：

我有4个editFields，当我输入所有字段并点击按钮＆＃34;随机播放器＆＃34; 它应该随机且不重复地在viewText中向下显示editFields中的所有玩家。

这是我的onlick功能代码：

 public void RandomPlayers(View v1){


    EditText text1 = (EditText)findViewById(R.id.editText1);
    TextView View1 = (TextView)findViewById(R.id.player1);
    EditText text2 = (EditText)findViewById(R.id.editText2);
    TextView View2 = (TextView)findViewById(R.id.player2);
    EditText text3 = (EditText)findViewById(R.id.editText3);
    TextView View3 = (TextView)findViewById(R.id.player3);
    EditText text4 = (EditText)findViewById(R.id.editText4);
    TextView View4 = (TextView)findViewById(R.id.player4);

    String value1 = text1.getText().toString();
    String value2 = text2.getText().toString();
    String value3 = text3.getText().toString();
    String value4 = text4.getText().toString();

    String[] players = {value1, value2, value3, value4};

    int index = new Random().nextInt(players.length);
    String random = (players[index]);
    View1.setText(random);
    View2.setText(random);
    View3.setText(random);
    View4.setText(random);

}

但问题是我一直为所有Textviews获得相同的随机名称

这是一个显示逻辑错误的图像：！[在此输入图像说明] [1]

请帮助我，告诉我我的错误感谢

Answer 1

尝试此解决方案就像魅力一样

public void RandomPlayers(View v1) {

        List<String> values = new ArrayList<String>();

        EditText text1 = (EditText) findViewById(R.id.editText1);
        TextView View1 = (TextView) findViewById(R.id.player1);
        EditText text2 = (EditText) findViewById(R.id.editText2);
        TextView View2 = (TextView) findViewById(R.id.player2);
        EditText text3 = (EditText) findViewById(R.id.editText3);
        TextView View3 = (TextView) findViewById(R.id.player3);
        EditText text4 = (EditText) findViewById(R.id.editText4);
        TextView View4 = (TextView) findViewById(R.id.player4);

        values.add(text1.getText().toString());
        values.add(text2.getText().toString());
        values.add(text3.getText().toString());
        values.add(text4.getText().toString());

        Collections.shuffle(values);

        View1.setText(values.get(0));
        View2.setText(values.get(1));
        View3.setText(values.get(2));
        View4.setText(values.get(3));

    }

Answer 2

您只生成一个随机数，因此索引始终相同，并且您只在所有TextView中获得一个名称。您可以像解释here那样对数组进行随机播放，并从中获取所有名称并将它们绑定到TextView。

Answer 3

您为所有视图设置了相同的随机值意思是你选择一次随机然后分配它你应该做类似的事情，但在每次任务之前再次随机调用

Answer 4

更改

int index = new Random().nextInt(players.length);
String random = (players[index]);
View1.setText(random);
View2.setText(random);
View3.setText(random);
View4.setText(random);

到

int index = new Random().nextInt(players.length);
String random = (players[index]);
View1.setText(random);

index = new Random().nextInt(players.length);
random = (players[index]);
View2.setText(random);

index = new Random().nextInt(players.length);
random = (players[index]);
View3.setText(random);

index = new Random().nextInt(players.length);
random = (players[index]);
View4.setText(random);

这样你会获得不同的数字，但无法保证不会有重复数据

如何进行非重复随机数组选择（android）？

4 个答案: