Question

除了 id 等于1和2的用户之外，如何进行查询以选择所有用户？

SELECT *
FROM $viewUsuarios
WHERE login LIKE '%$busca%'
  OR nome LIKE '%$busca%'
  OR sobrenome LIKE '%$busca%'
  OR senhasErradas LIKE '%$busca%'
  OR ADMIN LIKE '%$busca%'
  OR ativo LIKE '%$busca%'
  OR verificado LIKE '%$busca%'
  OR termoUso LIKE '%$busca%'
  OR versaoTermoUso LIKE '%$busca%'
ORDER BY id ASC LIMIT $contadornInicioRegistros,
                      $limiteRegistros

Answer 1

您将添加AND 您的查询应该如下所示。

SELECT * FROM $viewUsuarios 
           WHERE login LIKE '%$busca%' OR 
                 nome LIKE '%$busca%' OR 
                 sobrenome LIKE '%$busca%' OR 
                 senhasErradas LIKE '%$busca%' OR 
                 admin LIKE '%$busca%' OR 
                 ativo LIKE '%$busca%' OR 
                 verificado LIKE '%$busca%' OR 
                 termoUso LIKE '%$busca%' OR 
                 versaoTermoUso LIKE '%$busca%' AND 
                 id>2 
           ORDER BY id ASC 
           LIMIT $contadornInicioRegistros, $limiteRegistros

我希望它可以帮助..;）

Answer 2

此查询应该有效。

SELECT * FROM users WHERE id NOT IN (1, 2)

Answer 3

我相信一个简单的！=运算符就足够了。

实施例。 "SELECT * from {$viewUsarios} WHERE id != 1 AND id != 2";

来源：http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html

异常查询ID

3 个答案: