加入第三个MySQL表(重做)

时间:2014-05-12 02:22:56

标签: php html mysql

好的,所以我会尝试重新解释这个问题,因为似乎没有人理解我的目标。这是凌晨3点,所以我可能会稍微放松一下......但我会在这里尽我所能。

我目前正在撰写一篇文章&评论部分,用户可以在自己或其他用户墙上发布,因此,其他用户可以对这些帖子发表评论。与社交网络状态或一般论坛相同的事物。我有3张桌子......

Users
Statuses
Comments

用户包含标准......

userid
username
first_name
last_name
photo

状态包含有关每个用户发布的主要状态的任何信息,这些状态显示在用户配置文件中。因此,用户1可以在user2的个人资料上发布状态。这是状态表设计...

status_id (auto-i)
user_id (The users ID whos profile the post was added too)
sender_id (The user who sent the post or wrote it)
date (Date/Time was sent)
rate (This doesn't matter for a moment)
comments (This will count all the comments and display the number)
status (The actual status written out)

这些表在我的脚本中工作得很好,它连接了两个表并显示了用户信息(发布状态的人),例如他们的个人资料照片和姓名等......这是我当前的脚本,它没有任何问题所有...

//// GET STATUSES
                                    $user_id = $profile_data['userid'];
                              $data = mysql_query("
                              SELECT 
                     statuses.status_id, 
                     statuses.user_id,
                     statuses.sender_id,
                     statuses.date,
                     statuses.rate,
                     statuses.comments,
                     statuses.status,
                     users.userid, 
                     users.username, 
                     users.first_name, 
                     users.last_name, 
                     users.photo
                              FROM 
                                    statuses
                              LEFT JOIN 
                                    users
                              ON 
                                    statuses.sender_id=users.userid
                              WHERE 
                                    statuses.user_id = '{$profile_data['userid']}' 
                              ORDER BY 
                              `statuses`.`date` DESC
                               ") or die(mysql_error());  

                                  while($status = mysql_fetch_array( $data ))//added this
                                  {
                                  $statusid = $status['status_id'];
                                  $date = $status['date'];
                                  $rate = $status['rate'];
                                  $comments = $status['comments'];
                                  $userid = $status['user_id'];
                                  $senderid = $status['sender_id'];
                                  $statusbody = $status['status'];
                                  $username = $status['username'];
                                  $firstname = $status['first_name'];
                                  $lastname = $status['last_name'];
                                  $photo = $status['photo'];

                                  ?>
<form action="" method="POST" role="form" enctype="multipart/form-data" id="statusupdate" class="facebook-share-box">
            <div class="share">
                <div class="panel panel-default">
                      <div class="panel-heading"><a href="<? echo 'http://basecentre.co.uk/',$status["username"]; ?>"><img alt="" align="left" hspace="20" height="70" width="70" src="<? echo 'http://basecentre.co.uk/userimages/',$status["photo"]; ?>"> </a> <font size="+2"><i class="icon icon-comment-o"></i></font> <a href="<? echo 'http://basecentre.co.uk/',$status["username"]; ?>"><font size="+2"><?php echo $status['first_name']; ?> <?php echo $status['last_name'] ; ?></font></a> | <i class="icon icon-clock-o"></i> <a rel="tooltip" href="#" data-original-title="<? echo "". date('F j, Y, g:i a', strtotime($status['date']) + 60*60) .""; ?>"><?php echo "<strong>". date('j F', strtotime($status['date']) + 60*60) ."</strong>"; ?></a></div>
                      <div class="panel-body">
                        <div class="">
                            <?php echo $status['status']; ?>
                        </div>
                      </div>
                        <div class="panel-footer">
                                <div class="row">
                                <div class="col-md-7">
                                Comment | Like
                                </div>
                                </div>
                        </div>
                    </div>
            </div>
        </form>
                               </br>


<? 
                                  }


    ?>  

我为评论构建了一个新表。所以我可以去用户个人资料,阅读&#34;状态&#34;然后我可以添加评论...这是新表...

comment_id (auto-i)
status_id (added depending on which status you comment on. If the comment is on status id #5, the same number will be sent to this to connect the comments with the correct statuses)
sender_id (the id of the user who is sending the comment which would be $_session['userid'];
date (date the comment was sent)
rate (Doesn't matter yet)
comment (the actual comment written out).

我需要以某种方式将新的注释表加入到其他两个表中?我尝试添加另一个&#34;左连接&#34;但那不起作用?我对这些东西不太好。 我的目的是按发布日期的顺序让每条评论正确显示其连接状态。最近的底部...显示用户信息,以便您知道谁发布了评论。

希望这能让您更加了解,我希望有人可以提供帮助!!对不起它很长,但你们要求更多信息......谢谢!

编辑添加数据库记录:

状态表:

CREATE TABLE IF NOT EXISTS `statuses` (
  `status_id` int(25) NOT NULL AUTO_INCREMENT,
  `user_id` int(25) NOT NULL,
  `sender_id` int(25) NOT NULL,
  `date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  `rate` int(25) NOT NULL DEFAULT '0',
  `comments` int(25) NOT NULL DEFAULT '0',
  `status` text COLLATE utf8_unicode_ci NOT NULL,
  PRIMARY KEY (`status_id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=30 ;

--
-- Dumping data for table `statuses`
--

INSERT INTO `statuses` (`status_id`, `user_id`, `sender_id`, `date`, `rate`, `comments`, `status`) VALUES
(15, 11, 22, '2014-05-11 21:22:00', 0, 0, 'This is pretty damn cool! '),
(16, 11, 91, '2014-05-11 21:22:35', 0, 0, 'LOL how did you do this shit man?? Alll you gotta do now is add the comments ;) and likes! '),
(14, 11, 22, '2014-05-11 21:21:35', 0, 0, 'Hey budddy how are ya ? '),
(13, 11, 11, '2014-05-11 21:18:10', 0, 0, 'eerer'),
(11, 11, 11, '2014-05-11 21:10:33', 0, 0, 'Ho Ho!'),
(10, 11, 11, '2014-05-11 21:10:27', 0, 0, 'Hey hey ! '),
(28, 11, 11, '2014-05-12 00:47:02', 0, 0, 'LOL just another quick test ;) '),
(29, 22, 22, '2014-05-12 02:30:44', 0, 0, 'I should be able to delete this status... '),
(20, 11, 11, '2014-05-11 21:30:17', 0, 0, 'LOL WINNER'),
(21, 22, 11, '2014-05-11 23:31:18', 0, 0, 'Hey mate :D '),

(19, 11, 11, '2014-05-11 21:24:47', 0, 0, 'Not bad eh guys? ;P ');

评论表:

--
-- Table structure for table `comments`
--

CREATE TABLE IF NOT EXISTS `comments` (
  `comment_id` int(100) NOT NULL AUTO_INCREMENT,
  `status_id` int(25) NOT NULL,
  `user_id` int(25) NOT NULL,
  `sender_id` int(25) NOT NULL,
  `date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  `rate` int(25) NOT NULL DEFAULT '0',
  `comment` text COLLATE utf8_unicode_ci NOT NULL,
  PRIMARY KEY (`comment_id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=3 ;

--
-- Dumping data for table `comments`
--

INSERT INTO `comments` (`comment_id`, `status_id`, `user_id`, `sender_id`, `date`, `rate`, `comment`) VALUES
(1, 28, 11, 11, '2014-05-12 01:23:58', 0, 'Hmmm shall we see if we can get this working too!? Comments, here we come! '),
(2, 28, 11, 22, '2014-05-12 02:55:33', 0, 'This is not aidans comment! another username should appear!');

用户表:

    CREATE TABLE IF NOT EXISTS `users` (
  `userid` int(25) NOT NULL AUTO_INCREMENT,
  `first_name` varchar(25) COLLATE latin1_general_ci NOT NULL,
  `middle_name` varchar(25) COLLATE latin1_general_ci NOT NULL,
  `last_name` varchar(25) COLLATE latin1_general_ci NOT NULL,
  `email_address` varchar(50) COLLATE latin1_general_ci NOT NULL,
  `username` varchar(25) COLLATE latin1_general_ci NOT NULL,
  `password` varchar(255) COLLATE latin1_general_ci NOT NULL,
  `photo` varchar(50) COLLATE latin1_general_ci NOT NULL DEFAULT 'default.png',
  `date1` varchar(25) COLLATE latin1_general_ci NOT NULL,
  `date2` varchar(25) COLLATE latin1_general_ci NOT NULL,
  `date3` varchar(25) COLLATE latin1_general_ci NOT NULL,
  `birthplace` varchar(50) COLLATE latin1_general_ci NOT NULL,
  `gender` varchar(25) COLLATE latin1_general_ci NOT NULL,
  `about` varchar(250) COLLATE latin1_general_ci NOT NULL DEFAULT 'This information has not yet been updated.',
  `user_level` enum('0','1','2','3','4') COLLATE latin1_general_ci NOT NULL DEFAULT '0',
  `signup_date` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `last_login` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `activated` enum('0','1') COLLATE latin1_general_ci NOT NULL DEFAULT '0',
  `location` varchar(30) COLLATE latin1_general_ci NOT NULL,
  `premium` enum('0','1') COLLATE latin1_general_ci NOT NULL DEFAULT '0',
  `blocked` varchar(5) COLLATE latin1_general_ci NOT NULL DEFAULT '0',
  `fr_alert` varchar(6) COLLATE latin1_general_ci NOT NULL DEFAULT '0',
  `um_alert` varchar(6) COLLATE latin1_general_ci NOT NULL DEFAULT '0',
  PRIMARY KEY (`userid`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci COMMENT='Membership Information' AUTO_INCREMENT=92 ;

2 个答案:

答案 0 :(得分:1)

可能是这样的吗?不完全确定你的数据是什么样的,所以它可能是错误的..加入发送评论和状态ID的用户,然后通过评论DATE desc然后按状态DATE desc订购,这样它将提供最新的评论最多最近的帖子

SELECT -- added alias to your tables so its easier to read
    s.status_id, 
    s.user_id,
    s.sender_id,
    s.date,
    s.rate,
    s.comments as s_comment,
    s.status,
    u.userid as u_id, 
    u.username as u_name, 
    u.first_name as u_first, 
    u.last_name as u_last, 
    u.photo as u_photo,
    o.userid as o_id, 
    o.username as o_name, 
    o.first_name as o_first, 
    o.last_name as o_last, 
    o.photo as o_photo,
    c.comment as c_comment
FROM statuses s
LEFT JOIN users u ON s.sender_id=u.userid
LEFT JOIN comments c ON c.user_id = u.userid AND c.status_id = s.status_id
LEFT JOIN users o on o.userid = c.sender_id
WHERE s.user_id = '{$profile_data['userid']}' 
ORDER BY c.date DESC, s.date DESC

尝试一下,让我知道有什么问题..如果你可以用几行实际数据编辑你的帖子,比如一些帖子和状态的评论,像一个虚拟用户我可以我自己测试并澄清(将更容易加载)

答案 1 :(得分:1)

这个答案稍微改变了一些表结构,但其背后的核心思想是相同的。

使用我在这里创建的示例http://sqlfiddle.com/#!2/c1fa6e/1

基本上你可以INNER JOIN(来自两个表的结果)status表,两次users表,并使用AS运算符为它们创建别名。这允许您加入用户以获取个人资料所有者信息,以及发布状态的人员的信息。 (以下示例仅显示在配置文件所有者#1上发布的状态)

SELECT status.status_id, 
  profile_owner.username AS owner, 
  status_sender.username AS sender
  FROM status
  INNER JOIN users AS profile_owner
    ON profile_owner.user_id = status.user_id
  INNER JOIN users AS status_sender
    ON status_sender.user_id = status.sender_id
  WHERE profile_owner.user_id = 1;

结果

STATUS_ID OWNER     SENDER
1         User 1    User 2
2         User 1    User 4

然后添加评论,你LEFT JOIN评论表(可能并不总是有评论,在这种情况下这些字段将为空),然后获取评论员的用户详细信息我们INNER JOIN再次使用用户表,针对评论员ID获取其详细信息

SELECT status.status_id, 
  profile_owner.username AS owner, 
  status_sender.username AS sender,
  status.status,
  status_comment.comment_body,
  commentor.username AS commentor
  FROM status
  INNER JOIN users AS profile_owner
    ON profile_owner.user_id = status.user_id
  INNER JOIN users AS status_sender
    ON status_sender.user_id = status.sender_id
  LEFT JOIN status_comment
    ON status.status_id = status_comment.status_id
  LEFT JOIN users AS commentor
    ON status_comment.commentor_id = commentor.user_id
  WHERE profile_owner.user_id = 1;

给出这些结果

STATUS_ID OWNER    SENDER  STATUS                         COMMENT_BODY                          COMMENTOR
1         User 1   User 2  Test status on User1 by User2  User3 commenting on status by User2.  User 3
1         User 1   User 2  Test status on User1 by User2  User4 commenting on status by User2.  User 4
2         User 1   User 4  Test status on User1 by User4  (null)  (null)

这表明User1在其个人资料中发布了2个状态,一个是User2,有2条评论,另一个是User4,没有评论。然后,您可以在PHP中解析这些结果并进行适当显示。

一旦你将其分解,它就会非常直接。

你可以view it all in action here and play with it yourself on sqlfiddle

更新:使用您编辑到帖子中的数据库信息I have created an SQLFiddle,尝试向您展示如何将其应用到现有数据库。

这很直截了当,你似乎把我的例子翻译成你的代码有些错误。下面是更改了相应表名的正确查询。

SELECT statuses.status_id, 
  profile_owner.first_name AS owner, 
  status_sender.first_name AS sender,
  statuses.status,
  comments.comment,
  commentor.first_name AS commentor
  FROM statuses
  INNER JOIN users AS profile_owner
    ON profile_owner.userid = statuses.user_id
  INNER JOIN users AS status_sender
    ON status_sender.userid = statuses.sender_id
  LEFT JOIN comments
    ON statuses.status_id = comments.status_id
  LEFT JOIN users AS commentor
    ON comments.sender_id = commentor.userid
  WHERE profile_owner.userid = 11;

这将拉出用户ID 11的个人资料上发布的所有状态。它还会提取这些状态可能包含的任何评论。

**旁注... **我不确定您为什么要将sender_iduser_id存储在comments表格中。您的评论已经与状态相关,因此您知道它的发布对象,您只需要存储正在发表评论的人。

尝试将每个实体视为自己的对象。

你有3个对象

  • 用户
  • 状态
  • 注释

状态包含针对其发布的用户(status.user_id)以及发布该状态的用户(status.sender_id)。

评论具有针对其发布的状态(comments.status_id)以及发布评论的用户(comments.sender_id)。

无需再次在评论表中存储status.userid,因为您始终可以将其加入以获取该信息。