Question

我有另一种情况，我正在寻找一个可以显示null值的查询，

首先，我制作table1;

+---------+----------+
|id_table1| value    | 
+---------+----------+
|   1     | value1   | 
|   2     | value2   | 
|   3     | value3   | 
|   4     | value4   | 
|   5     | value5   |  
|   6     | value6   | 
|   7     | value7   | 
|   8     | value8   |  
|   9     | value9   | 
+---------+----------+

表2：

+---------+----------+
|id_table1| value    | 
+---------+----------+
|   P1    | valueP1  | 
|   P2    | valueP2  | 
+---------+----------+

这是我的关系表：

+---------+----------+---------+
|id_boss  | id_child |  answ   |  
+---------+----------+---------+
|   1     |     2    |    T    |
|   1     |     6    |    F    |
|   2     |     P1   |    T    |
|   2     |     4    |    F    |
|   6     |     P2   |    T    | 
|   6     |     8    |    F    |
+---------+----------+ --------+

我关注这个令人敬畏的answer以使我的第一个查询工作，请执行此SQLFiddle

+---------+-----------+-----------+
|id_boss  | child_T   | child_F   |     
+---------+-----------+-----------+
| value1  |  value2   |  value6   |
| value2  |  valueP1  |  value4   |
| value6  |  valueP2  |  value8   |
+---------+-----------+-----------+

然后这是我的新问题，

来自关系表，比方说，我正在删除一些id_child值，所以我可以稍后填写它，

+---------+----------+---------+
|id_boss  | id_child |  answ   |  
+---------+----------+---------+
|   1     |     2    |    T    |
|   1     |     6    |    F    |
|   2     |     P1   |    T    |
|   2     |     4    |    F    |
|   6     |          |    T    | 
|   6     |          |    F    |
|   4     |          |    T    | 
|   4     |          |    F    |
+---------+----------+ --------+

然后我正在寻找一种方法让我的查询看起来像这样：

+---------+-----------+-----------+
|id_boss  | child_T   | child_F   |     
+---------+-----------+-----------+
| value1  |  value2   |  value6   |
| value2  |  valueP1  |  value4   |
| value6  |  `null`   |  `null`   |
| value4  |  `null`   |  `null`   |
+---------+-----------+-----------+

Answer 1

试试这个：

SELECT (SELECT value FROM table1 WHERE table1.id_table1 = r1.id_boss) AS id_boss,
    COALESCE( (SELECT value FROM table1 WHERE table1.id_table1 = r1.id_child),
              (SELECT value FROM table2 WHERE table2.id_table2 = r1.id_child)
            ) AS child_T,
    COALESCE( (SELECT value FROM table1 WHERE table1.id_table1 = r2.id_child),
              (SELECT value FROM table2 WHERE table2.id_table2 = r2.id_child)
            ) AS child_F
FROM r_table AS r1 , r_table AS r2 
WHERE r1.id_boss = r2.id_boss AND r1.answ = 'T'  AND r2.answ = 'F';

SQL Fiddle

它对我有用，但如果你有问题请告诉我。

SQLite：选择语句并显示“null”值

1 个答案: