我有一个包含三个参数的对象(称为表达式):term1 operation term2其中term1和term2是对象,operation是一个字符串。处理对象的逻辑可以处理term1或term2是字符串或递归场景,其中它们包含嵌入式表达式。
即
[DataContract] public class expression
{
[DataMember] public object term1 { get; set; }
[DataMember] public string operation { get; set; }
[DataMember] public object term2 { get; set; }
}
当我尝试对term1 / term2为简单字符串的对象进行反序列化时,它的效果很好,即
{ term1: "foo", operation: "=", term2: "bar" }
将使用C#JavaScriptSerializer和以下代码正确反序列化:
public T deserialize_json<T>(string json_string)
{
JavaScriptSerializer serializer = new JavaScriptSerializer();
return (T)serializer.Deserialize<T>(json_string);
}
但是,当我尝试提交嵌套对象时,即:
{
term1:
{
term1: "foo", operation: "=", term2: "bar"
},
operation: "or",
term2:
{
term1: "foo", operation: "equals", term2: "baz"
}
}
JavaScriptSerializer会将term1和term2反序列化为'System.Collections.Generic.Dictionary
2 [System.String,System.Object]&#39;`
有什么想法吗?
我的方法调用很简单:
expression expr = deserialize<expression>(data);
答案 0 :(得分:1)
您需要序列化有关term1和term2类型的信息。为此,您可以使用Newtonsoft.Json库。
试试这段代码:
expression model = new expression() { term1 = new expression() { operation = " + " } };
string content = ModelManager<expression>.SaveToString(model);
/* content =
{
"$type": "Test.expression, Test",
"term1": {
"$type": "Test.expression, Test",
"operation": " + "
}
}
*/
var model2 = ModelManager<expression>.LoadFromString(content);
string content2 = ModelManager<expression>.SaveToString(model2);
// content == content2
public static class ModelManager<T>
{
public static T LoadFromString(string content)
{
using (var sr = new StringReader(content))
using (var jr = new JsonTextReader(sr))
return GetSerializer().Deserialize<T>(jr);
}
public static string SaveToString(T model)
{
StringBuilder sb = new StringBuilder(512);
using (var sw = new StringWriter(sb, System.Globalization.CultureInfo.InvariantCulture))
using (var jtw = new JsonTextWriter(sw))
GetSerializer().Serialize(jtw, model);
return sb.ToString();
}
private static Newtonsoft.Json.JsonSerializer GetSerializer()
{
return new Newtonsoft.Json.JsonSerializer()
{
NullValueHandling = Newtonsoft.Json.NullValueHandling.Ignore,
DefaultValueHandling = Newtonsoft.Json.DefaultValueHandling.Include,
TypeNameHandling = Newtonsoft.Json.TypeNameHandling.Objects,
TypeNameAssemblyFormat = System.Runtime.Serialization.Formatters.FormatterAssemblyStyle.Simple,
Formatting = Formatting.Indented,
MaxDepth = null,
ReferenceLoopHandling = ReferenceLoopHandling.Error,
PreserveReferencesHandling = PreserveReferencesHandling.None
};
}
}