我想知道如何将dynmically列添加到gridview。网格视图假设获得用户输入。我知道如何将itemtemplate用于特定的列数,但我不知道如何使用itemtemplate(文本框)字段动态添加列并制作数据绑定。
答案 0 :(得分:6)
您需要创建一个实现 ITemplate 的类,完整代码如下:
public class DynamicTemplateField : ITemplate
{
public void InstantiateIn(Control container)
{
//define the control to be added , i take text box as your need
TextBox txt1 = new TextBox();
txt1.ID = "txt1";
container.Controls.Add(txt1);
}
}
//Method to bind the Grid View
public void BindData()
{
TemplateField temp1 = new TemplateField(); //Create instance of Template field
temp1.HeaderText = "New Dynamic Temp Field"; //Give the header text
temp1.ItemTemplate = new DynamicTemplateField(); //Set the properties **ItemTemplate** as the instance of DynamicTemplateField class.
gv.Columns.Add(temp1); //add the instance if template field in columns of grid view
//Bind the grid view
gv.DataSource = [your data source];
gv.DataBind();
}
<强>的RowDataBound 强>
protected void gv_RowDataBound(object sender, System.Web.UI.WebControls.GridViewRowEventArgs e)
{
if(e.Row.RowType == DataControlRowType.DataRow)
{
TextBox txt1 = e.Row.FindControl("txt1") as TextBox;
txt1.Text = e.Row.DataItem["Name"]; //Assign any column value of your datasource
}
}
.aspx页面
<asp:GridView ID = "gv" runat = "server" >
<Columns>
</Columns>
</asp:GridView>
您可以操纵 DynamicTemplateField 类来添加不同类型的控件