表单提交后使用jquery fancybox插件显示弹出成功消息

时间:2014-05-11 05:14:17

标签: php jquery forms popup fancybox

表单验证成功后,我想使用fancybox插件显示弹出成功的消息。

这是我的PHP代码 -

<?php 

if(isset($_POST['cfsubmit'])){  

//if no erros, echo the results 
if(!$errorExists){
    echo "<div id='c_confirm'><p><span class='check_mark'></span>Thank you for contacting With us. One of our customer service representatives will get back to you within 24 hours.</p></div>";
            $emailTo = "myemail@gmail.com";
    if (!isset($emailTo) || ($emailTo == '') ){
        $emailTo = get_option('admin_email');
    }

    $subject = 'Contact Form from '.$fname;
    $body = "First Name: $fname \n\nLast Name: $lname \n\nCheck In date: $check_in_date \n\nCheck Out date: $check_out_date \n\nApartment type: $apart_type \n\nPhone: $phone \n\nEmail: $email \n\nComments: $comments";
    $headers = 'From: '.$fname.' <'.$email.'>' . "\r\n" . 'Reply-To: ' . $email . "\r\n";
           wp_mail($emailTo, $subject, $body, $headers);


}else{
    echo "<h3>Error!</h3>".$errors;
}

}?>

我想在弹出框中显示此消息。使用jquery fancybox插件。

<div id='c_confirm'><p><span class='check_mark'></span>Thank you for contacting With us. One of our customer service representatives will get back to you within 24 hours.</p></div>

1 个答案:

答案 0 :(得分:1)

假设您已正确加载jQuery和fancybox js和css文件,您可以这样做:

if(!$errorExists){
    $fancymessage = "<div id='c_confirm'><p><span class='check_mark'></span>Thank you for contacting With us. One of our customer service representatives will get back to you within 24 hours.</p></div>";
    ?>
    <script>
    jQuery(document).ready(function($){
        $.fancybox("<?php echo $fancymessage; ?>");
    });
    </script>
    <?php 
    $emailTo = "myemail@gmail.com";
    if (!isset($emailTo) || ($emailTo == '') ){
        $emailTo = get_option('admin_email');
    }
    ... etc.

<强> JSFIDDLE