Question

例如，我想输出数字6，但是我所见过的每个运算符重载的例子都在参数中包含一个“const”对象。

Class MyClass
{
    private:
        int num;
    public:
        //Setter
        void setNum(int x)            {num = x;}

        //Getter
        int getNum()                  {return x;}

        //Overloading + Operator
        MyClass operator + (int add)
        {
        }
};

int Main()
{
    MyClass test;
    test.setNum(2);
    test = test + 4;
    cout << test.getNum();
    return 0;
}

Answer 1

以下是执行所需操作的代码：

class MyClass
{
    private:
        int num;
    public:
        //Setter
        void setNum(int x)            {num = x;}

        //Getter
        int getNum()                  {return num;}

        //Overloading + Operator
        MyClass operator + (int add)
        {
            MyClass copy;
            copy.num = num + add;
            return copy;
        }
};

int main()
{
    MyClass test;
    test.setNum(2);
    test = test + 4;
    std::cout << test.getNum();
    return 0;
}

您的代码有许多已修复的编译器错误。例如，Class应该是class，Main应该是main。

在C ++中，如何在不通过参数传递对象的情况下重载运算符？

1 个答案: