Spinner导致应用程序崩溃

时间:2014-05-10 17:47:56

标签: java android spinner

我是Stackoverflow的新手,也是Android的编程

我在AndroidApp中完成了这段代码:

public class MainActivity extends ActionBarActivity {

private Spinner spinner;
private LinkedList<Integer> list;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    if (savedInstanceState == null) {
        getSupportFragmentManager().beginTransaction()
                .add(R.id.container, new PlaceholderFragment())
                .commit();
    }

    this.ageSpinner();


}

private void ageSpinner(){

    list = new LinkedList<Integer>();
    spinner = (Spinner) this.findViewById(R.id.spinner1);

    for(Integer i=0; i<=4; i++){


        list.add(i);

    }

    ArrayAdapter<Integer> spinnerAdapter = new ArrayAdapter<Integer>(this, android.R.layout.simple_spinner_item, list);
    spinnerAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);

    spinner.setAdapter(spinnerAdapter);

}

我的logCat会给我一个NullPointerException

我试过这个代码,将Linkelist更改为ArrayList,String Array,但我的应用程序崩溃了。

2 个答案:

答案 0 :(得分:1)

您需要实例化Spinner,以使其不为空。

rootView.findViewById(R.id.spinner1)方法中使用onCreate可以解决问题。

答案 1 :(得分:1)

试试此代码

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    if (savedInstanceState == null) {
        getSupportFragmentManager().beginTransaction()
                .add(R.id.container, new PlaceholderFragment())
                .commit();
    }
spinner = (Spinner)findViewById(R.id.spinner1);
ageSpinner();
ArrayAdapter<Integer> spinnerAdapter = new ArrayAdapter<Integer>(this,             android.R.layout.simple_spinner_item, list);
spinnerAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spinner.setAdapter(spinnerAdapter);
}
 private void ageSpinner(){

    list = new ArrayList<Integer>();
    for(int i=0; i<=4; i++){
        list.add(i);


    }
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