Question

我有以下查询：

SELECT sa.*, d.day, TIME_FORMAT(timefrom.time, '%H:%i') AS time_from, TIME_FORMAT(timeto.time, '%H:%i') AS time_to
            FROM staff s
            INNER JOIN staff_availability sa
            ON sa.staff_id = s.staff_id 
            INNER JOIN days d 
            ON d.day_id = sa.day_id
            LEFT JOIN time_slots AS timefrom
            ON timefrom.time_slot_id = sa.time_from 
            LEFT JOIN time_slots AS timeto
            ON timeto.time_slot_id = sa.time_to
            INNER JOIN users u
            ON s.user_id = u.user_id
            WHERE u.user_id = :user_id

我使用别名time_from和time_to作为time_slots表中选择的格式化时间，这些时间与staff_availability表连接在一起。

查询返回以下内容：

staff_availability_id   staff_id   day_id   time_from(join)  time_to(join)   day    time_from (alias)   time_to (alias)

有什么方法可以从结果中排除连接列？

Answer 1

你必须手动选择它们。

更改此

SELECT sa.*

到

SELECT sa.staff_availability_id ,  sa.staff_id,....--what ever you want to select and dont select those you mentioned

Answer 2

选择列，

SELECT sa.staff_availability_id ,sa.staff_id,d.day, TIME_FORMAT(timefrom.time, '%H:%i') AS time_from, TIME_FORMAT(timeto.time, '%H:%i') AS time_to
            FROM staff s
            INNER JOIN staff_availability sa
            ON sa.staff_id = s.staff_id 
            INNER JOIN days d 
            ON d.day_id = sa.day_id
            LEFT JOIN time_slots AS timefrom
            ON timefrom.time_slot_id = sa.time_from 
            LEFT JOIN time_slots AS timeto
            ON timeto.time_slot_id = sa.time_to
            INNER JOIN users u
            ON s.user_id = u.user_id
            WHERE u.user_id = :user_id

从mysql查询中排除已连接的列

2 个答案: