在SQL Server数据库中,我有两个表,一个是另一个的父表。子表与父项具有多对一关系。我需要为每个父级返回一条记录,其中包含最相应的子表记录。但是我无法弄清楚如何做到这一点。
以下是我现在的查询:
SELECT DISTINCT
products.id,
sku,
name,
mediaid
FROM
products
INNER JOIN
productmedia ON products.id = productmedia.productid
WHERE
sku IN ('HCFL 207 23 (A)','HCFL 207 22 (A)','HCFL 207 21 (A)','HCFL 207 20 (A)')
AND productmedia.sort = 100
我得到以下内容:
183816 HCFL 207 20 (A) HCFL SERIES- 2-BOLT FLANGE, ECCENTRIC LOCKING COLLAR, BORE DIA. 1 1/4", WIDE INNER RACE INSERT -ASIAN 2929082
183816 HCFL 207 20 (A) HCFL SERIES- 2-BOLT FLANGE, ECCENTRIC LOCKING COLLAR, BORE DIA. 1 1/4", WIDE INNER RACE INSERT -ASIAN 2929083
183817 HCFL 207 21 (A) HCFL SERIES-2-BOLT FLANGE, ECCENTRIC LOCKING COLLAR, BORE DIA. 1 5/16", WIDE INNER RACE INSERT-ASIAN 2929138
183817 HCFL 207 21 (A) HCFL SERIES-2-BOLT FLANGE, ECCENTRIC LOCKING COLLAR, BORE DIA. 1 5/16", WIDE INNER RACE INSERT-ASIAN 2929139
183818 HCFL 207 22 (A) HCFL SERIES- 2-BOLT FLANGE, ECCENTRIC LOCKING COLLAR, BORE DIA. 1 3/8", WIDE INNER RACE INSERT -ASIAN 2929086
183818 HCFL 207 22 (A) HCFL SERIES- 2-BOLT FLANGE, ECCENTRIC LOCKING COLLAR, BORE DIA. 1 3/8", WIDE INNER RACE INSERT -ASIAN 2929087
183819 HCFL 207 23 (A) HCFL SERIES- 2-BOLT FLANGE, ECCENTRIC LOCKING COLLAR, BORE DIA. 1 7/16", WIDE INNER RACE INSERT -ASIAN 2929084
183819 HCFL 207 23 (A) HCFL SERIES- 2-BOLT FLANGE, ECCENTRIC LOCKING COLLAR, BORE DIA. 1 7/16", WIDE INNER RACE INSERT -ASIAN 2929085
答案 0 :(得分:0)
;with cte as(
select s.id studentId, s.name, c.class,
ROW_NUMBER() over(partition by class order by s.id) rn
from Student s
inner join class c on s.classId = c.id
)
select * from cte where rn = 1
您可以通过s.id"更改"顺序到您认为基于订购结果的任何其他列。
答案 1 :(得分:0)
CROSS APPLY
是你的朋友:
SELECT DISTINCT
products.id,
sku,
name,
mediaid
FROM
products
CROSS APPLY (
SELECT TOP(1)
* -- List the required columns!
FROM
productmedia
WHERE
products.id = productmedia.productid
AND productmedia.sort = 100
ORDER BY
YourOrderColumn -- Change it to your required order!
) AS X
WHERE
sku IN ('HCFL 207 23 (A)','HCFL 207 22 (A)','HCFL 207 21 (A)','HCFL 207 20 (A)')