我想要一份除了其他数据之外修改了给定用户故事的所有人的列表。
我正在使用以下JSON数据查询Rally Lookback REST API:
{
"find" : { "FormattedID": "$STORY" },
"fields" : ["ObjectID", "_ValidFrom", "_ValidTo", "Blocked", "c_KanbanState", "Owner"],
"compress" : true
}
通过此查询,我得到了所有者的OID,如下所示:
{
"_ValidFrom": "2014-05-09T15:18:29.912Z",
"_ValidTo": "9999-01-01T00:00:00.000Z",
"ObjectID": 18326652440,
"Blocked": false,
"Owner": 13786838413,
"c_KanbanState": "Accepted"
}
有没有办法保湿所有者领域?我想看看“John Smith”,但我会选择“jsmith@example.com”。
如果我必须使用WSAPI,有没有办法一次查询一组所有者OID - 如果是这样,样本会有用 - 或者我需要循环遍历值集合并单独查询每个所有者?
答案 0 :(得分:1)
答案 1 :(得分:1)
正如Trever所说,在Lookback API中,用户字段无法保持水分。
就使用wsapi水合用户字段的示例而言,下面的代码使用shapshotstore获取'_PreviousValues.Blocked' : {$exists: true}
的快照,然后使用Rally.data.ModelFactory获取每个用户的DisplayName快照。
Ext.define('CustomApp', {
extend: 'Rally.app.App',
componentCls: 'app',
scopeType: 'iteration',
comboboxConfig: {
labelWidth: 100,
width: 300
},
launch: function() {
var that = this;
var iterationComboBox = Ext.create('Rally.ui.combobox.IterationComboBox',{
listeners:{
ready: function(combobox){
var iterationOid = combobox.getRecord().get('ObjectID');
that._loadStories(iterationOid);
},
select: function(combobox){
var iterationOid = combobox.getRecord().get('ObjectID');
this._loadStories(iterationOid);
},
scope: this
}
});
this.add(iterationComboBox);
},
_loadStories:function(iterationOid){
var that = this;
var snapshotStore = Ext.create('Rally.data.lookback.SnapshotStore', {
autoLoad:true,
find: {
'_TypeHierarchy': 'HierarchicalRequirement',
'_ProjectHierarchy': 12352608219,
'_PreviousValues.Blocked' : {$exists: true},
'Iteration': iterationOid
},
fetch: ['Name','FormattedID','ScheduleState','Blocked','_ValidFrom','_ValidTo', 'BlockedReason','Owner'],
order: 'OpenedDate DESC',
hydrate: ['Blocked','ScheduleState'],
compress: true,
listeners: {
load: function(store,records,success){
console.log("loaded %i records", records.length);
that._onStoriesLoaded(snapshotStore, records);
},
scope:this
}
});
},
_onStoriesLoaded:function(store, records){
var that = this;
var promises = [];
_.each(records, function(story) {
promises.push(that._hydrateOwner(story, that));
});
Deft.Promise.all(promises).then({
success: function(results) {
that._stories = results;
console.log('that._stories', that._stories);
that._makeGrid();
}
});
},
_hydrateOwner:function(story, scope){
var deferred = Ext.create('Deft.Deferred');
var that = scope;
var ownerDisplayName = null;
var userOid = story.get('Owner');
var storyBlocked = story.get('Blocked');
Rally.data.ModelFactory.getModel({
type: 'User',
scope: this,
success: function(model, operation) {
fetch: ['UserName', 'DisplayName'],
model.load(userOid, {
scope: this,
success: function(record, operation) {
owner = record.get('DisplayName');
var fid = story.get('FormattedID');
var state = story.get('ScheduleState');
var name = story.get('Name');
var blocked = story.get('Blocked');
result = {
"fid" : fid,
"name" : name,
"state" : state,
"blocked" : blocked,
"owner" : owner
};
deferred.resolve(result);
}
});
}
});
return deferred;
},
_makeGrid: function() {
if (this.down('#grid')) {
this.down('#grid').destroy();
}
var gridStore = Ext.create('Rally.data.custom.Store', {
data: this._stories
});
var _grid = Ext.create('Rally.ui.grid.Grid', {
itemId: 'grid',
store: gridStore,
columnCfgs: [
{
text: 'Name', dataIndex: 'name'
},
{
text: 'FormattedID', dataIndex: 'fid'
},
{
text: 'ScheduleState', dataIndex: 'state'
},
{
text: 'Blocked', dataIndex: 'blocked'
},
{
text: 'Owner', dataIndex: 'owner'
}
]
});
this.add(_grid);
this._grid.reconfigure(gridStore);
}
});
答案 2 :(得分:1)
除了尼克和特雷弗所说的,如果你想知道谁修改了一个特定的故事,那么你所寻找的领域就是“_User”。所有者是所有者,_User是谁创建了修订版。尼克的示例代码可以调整为水合_User,因为它只是像所有者一样的OID。
警告:如果有人更改了只有一个大文本字段(如说明),则不会创建快照,因此不会返回。