has_secure_password不适用于JSON,但它适用于表单

时间:2014-05-09 16:24:34

标签: json ruby-on-rails-4 strong-parameters

我正在使用方法

has_secure_password 

在我理解的用户模型上创建了两个虚拟字段:

Password 
Password_confirmation

并验证它们的前置,所以在我身边,我正在做这些其他验证:

validates :password  , length: {minimum: 6} 
validates :password_confirmation  , length: {minimum: 6}

在我看来,我有这样的形式:

<%= form_for :user, url:{controller: 'users', action: 'create'}, html:{class:"form-horizontal"}  do |f| %>

        <div class="form-group">
          <%= f.label(:name, "Nombre", class:"control-label col-sm-1") %>
          <div class="col-sm-3">
          <%= f.text_field(:name, class:"form-control") %>
          </div>
        </div>

        <div class="form-group ">
              <%= f.label(:last_name, "Apellido", class:"control-label col-sm-1") %>
              <div class="col-sm-3">
                    <%= f.text_field(:last_name,  class:"form-control ") %>
              </div>
        </div>

        <div class="form-group ">
              <%= f.label(:cellphone, "Celular", class:"control-label col-sm-1") %>
              <div class="col-sm-3">
              <%= f.text_field(:cellphone, class:"form-control") %>
                </div>
        </div>

        <div class="form-group ">
              <%= f.label(:phone, "Telefono", class:"control-label col-sm-1") %>
              <div class="col-sm-3">
              <%= f.text_field(:phone, class:"form-control") %>
                </div>
        </div>

        <div class="form-group ">
              <%= f.label(:address, "Direccion", class:"control-label col-sm-1") %>
          <div class="col-sm-3">
              <%= f.text_field(:address, class:"form-control") %>
            </div>

        </div>

        <div class="form-group ">
              <%= f.label(:email, "Correo", class:"control-label col-sm-1") %>
            <div class="col-sm-3">
              <%= f.text_field(:email, class:"form-control") %>
            </div>
        </div>

        <div class="form-group ">
            <%= f.label(:password, "Contraseña", class:"control-label col-sm-1") %>
            <div class="col-sm-3">
                <%= f.password_field(:password, class:"form-control") %>
            </div>
        </div>

      <div class="form-group ">
        <%= f.label(:password_confirmation, "Confirmar Contraseña", class:"control-label col-sm-1") %>
        <div class="col-sm-3">
          <%= f.password_field(:password_confirmation, class:"form-control") %>
        </div>
      </div>

        <div class="form-group ">
            <%= f.label(:city_id, "Ciudad", class:"control-label col-sm-1") %>
            <div class="col-sm-3">
                 <%= f.select(:city_id, @cities.map {|c| [c.name, c.id]}) %>
            </div>

        </div>

        <div class="form-buttons">
            <%= submit_tag("Create Section") %>
        </div>

  <% end %>

并且控制器具有以下操作:

def create

@user = User.new(user_params)
    if @user.save
      session[:user_id] = @user.id
      redirect_to controller: "users", action: "show"

    else
      @cities = City.all
      render 'new'
    end
  end

private

     def user_params
        params.require(:user).permit(:name, :last_name, :email, :address, :password,    :password_confirmation, :cellphone, :city_id, :phone)
      end

因此,当用户提交表单时,用字段password_digest下的加密密码创建用户,并且它可以正常工作。

我的实际问题是它的控制器让客户端通过发送json创建一个新用户,这是api控制器的方法:

respond_to :json

def create
    respond_with User.create(user_params)
end 

private

  def user_params
    params.require(:user).permit(:name, :last_name, :email, :address, :password, :password_confirmation, :cellphone, :city_id, :phone)
  end

当我发送这个JSON时:

var ad = {

            name:"juan",
            last_name:"paco",
            cellphone:"1234567890",
            phone:"1234567890",
            address:"porche",
            password:"porche",
            password_confirmation:"porche",
            email:"kkk@hj.com",
            city_id: 1,

        };

localhost.com:3000/api/v1/users/create

我得到:

{"errors":{"password":["can't be blank","is too short (minimum is 6 characters)"],"password_confirmation":["is too short (minimum is 6 characters)"]}}

2 个答案:

答案 0 :(得分:2)

看起来这个问题与参数包装http://api.rubyonrails.org/classes/ActionController/ParamsWrapper.html

有关

由于您的json参数不在根节点下(并且您可能在config / initializers / wrap_parameters.rb中打开了参数包装),因此这些字段将自动包装在与控制器同名的根目录中({ {1}})。由于user是一个虚拟属性,password不会返回它,因此它不会被包装:

  

在没有:include或:exclude选项设置的ActiveRecord模型上,它   只会包装类方法返回的参数   attribute_names。

我认为这里正确的解决方案是在attribute_names的{​​{1}}列表中指定password,将其添加到include的顶部

wrap_parameters

或使用UsersController根节点

发出JSON请求
wrap_parameters include: User.attribute_names + [:password]

答案 1 :(得分:0)

我找到了一个解决方案,也许没有最实用的解决方案,但是它确实有效......

我将创建方法更改为:

 def create
    new_parms = user_params
    new_parms[:password] = params[:password]
    new_parms[:password_confirmation] = params[:password_confirmation]
    respond_with User.create(new_parms)
  end

因为我正在检查rails服务器日志,我在html请求的params和JSON请求上的params中看到了一些不同之处。

当有人提交表格时我得到了这个:

Started POST "/users/create" for 127.0.0.1 at 2014-05-09 16:56:07 -0400
Processing by UsersController#create as HTML
  Parameters: {"utf8"=>"✓", "authenticity_token"=>"5HZn9RRbdNAzSirAb9FauNYj/Jr/AAkKBecTvzrih/8=", "user"=>{"name"=>"", "last_name"=>"", "cellphone"=>"", "phone"=>"", "address"=>"", "email"=>"", "password"=>"[FILTERED]", "password_confirmation"=>"[FILTERED]", "city_id"=>"1"}, "commit"=>"Create Section"}

当我发送JSON请求时,我得到了这个:

Started GET "/api/v1/users/creando" for 127.0.0.1 at 2014-05-09 16:58:34 -0400
Processing by API::V1::UsersController#creando as JSON
  Parameters: {"name"=>"juan", "last_name"=>"paco", "cellphone"=>"1234567890", "phone"=>"1234567890", "address"=>"porche", "password"=>"[FILTERED]", "password_confirmation"=>"[FILTERED]", "email"=>"kkk@hj.com", "city_id"=>1, "commit"=>"Create Section", "authenticity_token"=>"5HZn9RRbdNAzSirAb9FauNYj/Jr/AAkKBecTvzrih/8=", "user"=>{"name"=>"juan", "last_name"=>"paco", "cellphone"=>"1234567890", "phone"=>"1234567890", "address"=>"porche", "email"=>"kkk@hj.com", "city_id"=>1}}

我认为这是为form_for创建User对象的实例而de JSON没有人可以告诉我为什么要修复它?