从xml文件中插入带有xmltype列的表

时间:2014-05-09 11:50:14

标签: oracle insert oracle11g xmltype

以下是我插入xml文件的查询

INSERT INTO sampletagtable VALUES ( 1 , XMLType(bfilename('xmldir3', 'book.xml') , nls_charset_id('AL32UTF8') ));

在此之前,我通过以下查询创建了xmldir3,

CREATE OR REPLACE DIRECTORY xmldir3 AS '/opt/user/nishanth/xmldir';

这里/opt/user/nishanth是我的linux操作系统中的一个目录。

book.xml位于指定的目录中。

我收到以下错误,

SQL Error: ORA-22285: non-existent directory or file for FILEOPEN operation
ORA-06512: at "SYS.XMLTYPE", line 296
ORA-06512: at line 1
22285. 00000 -  "non-existent directory or file for %s operation"
*Cause:    Attempted to access a directory that does not exist, or attempted
           to access a file in a directory that does not exist.
*Action:   Ensure that a system object corresponding to the specified
           directory exists in the database dictionary, or
           make sure the name is correct.

1 个答案:

答案 0 :(得分:1)

您创建的目录为xmldir3,这是一个不带引号的标识符,因此它在数据字典中是大写的。但是你以小写的方式提到它。你需要使用:

bfilename('XMLDIR3', 'book.xml')

您可以通过查询all_directories视图来检查实际目录名称:

SQL> CREATE OR REPLACE DIRECTORY xmldir3 AS '/opt/user/nishanth/xmldir';

Directory created.

SQL> SELECT directory_name, directory_path FROM all_directories;

DIRECTORY_NAME                 DIRECTORY_PATH
------------------------------ ----------------------------------------
XMLDIR3                        /opt/user/nishanth/xmldir
...