Question

我想在zend 1中将多行插入数据库，但是我有一个错误：

致命错误：未捕获异常'Zend_Controller_Dispatcher_Exception'，消息'D：\ HR_New \ 30_SourceManagement \ HRSystem \ library \ Zend \ Controller \ Dispatcher \ Standard.php中有'无效控制器指定（错误）'：248堆栈跟踪：#0 D： \ HR_New \ 30_SourceManagement \ HRSystem \ library \ Zend \ Controller \ Front.php（954）：Zend_Controller_Dispatcher_Standard-＆gt; dispatch（Object（Zend_Controller_Request_Http），Object（Zend_Controller_Response_Http））＃1 D：\ HR_New \ 30_SourceManagement \ HRSystem \ library \ Zend \ Application \ Bootstrap \ Bootstrap.php（97）：Zend_Controller_Front-＆gt; dispatch（）＃2 D：\ HR_New \ 30_SourceManagement \ HRSystem \ library \ Zend \ Application.php（366）：Zend_Application_Bootstrap_Bootstrap-＆gt; run（）＃3 D：\ HR_New \ 30_SourceManagement \ HRSystem \ index.php（11）：Zend_Application-＆gt; run（）＃4 {main}抛出D：\ HR_New \ 30_SourceManagement \ HRSystem \ library \ Zend \ Controller \ Dispatcher \ Standard.php在第248行

这是我的代码：在* .phtml中，我有一个ajax函数：

$('#btnSubmit').bind({
        "click": function(){
            $.ajax({
                type: 'GET',
                dataType: 'JSON',
                url: 'change-authorize-data',
                data: {
                        arrCode: arrCode,
                },
                success: function(data){
                    alert("authorize success !");
                },
                error: function(xhr, ajaxOptions, thrownError){
                    alert("authorize fail!");
                    console.log("xhr.status: "+xhr.status);
                    console.log("thrownError: "+thrownError);
                }
            });
        }   
    });

使用arrCode是一个对象，数据为：

arrCode[0][role_id]:4
arrCode[0][screen_id]:9SE902
arrCode[0][access_status]:1
arrCode[1][role_id]:5
arrCode[1][screen_id]:9SE902
arrCode[1][access_status]:1

我的控制器的功能如下：

public function changeAuthorizeDataAction(){
    $authorizeModel = new Default_Model_AuthorizeModel();
    if($this->_request->isGet()){
        $arrCode = $this->_request->getParam ( 'arrCode' );
        try {
            $authorize = $authorizeModel->addAuthorize($arrCode);
        } catch (Exception $e) {
            $authorize = $authorizeModel->updateAuthorize($arrCode);
        }

        $this->_response->setBody ( json_encode ( $authorize ) );
    }
}

这个我的模型有一个函数：

public function addAuthorize($insertArr){
     $strInsert = " insert into `tbl_authorization` (`role_id`,`screen_id`,`access_status`) values _value";
    $valueInsert = "";
    $count = count($insertArr);
    if($count > 0) {
        for($i = 0 ; $i<$count ; $i++) {
            $valueInsert .= "("
                    .$insertArr[$i]['role_id'] .",'"
                            .$insertArr[$i]['screen_id']. "',"
                                    .$insertArr[$i]['access_status'] .")";

            if($i < $count - 1) {
                $valueInsert .= ",";
            }
        }

        $newStr = str_replace("_value",$valueInsert,$strInsert);

        try {
            //die($newStr);
            $this->db->query($newStr);
        } catch (Exception $e) {

        }
    }
}

当我使用die（$ newStr）时，我得到了一个SQL。但$ this-＆gt; db-＆gt;查询（$ newStr）未运行。谁能帮我？谢谢！

Answer 1

我找到了理由：

$this->view->layout ()->disableLayout ();
$this->_helper->viewRenderer->setNoRender ( TRUE );

我有：

public function userauthorizingAction() {
    $userInfo = Zend_Auth::getInstance ()->getStorage ()->read ();
//add tow rows below
    $this->view->userLogin = $userInfo->employee_name;
    $this->EmpID = $userInfo->employee_id;

    $requestForm = new Default_Model_RequestformModel ();
    $this->view->role = $requestForm->getRoleUserCurent ( $this->EmpID );

    if($this->_request->isGet()){
        $sreenModel = new Default_Model_ScreenModel();
        $roleModel = new Default_Model_RoleModel();

        $this->view->screenData = $sreenModel->loadScreenList();
    }
}

将数组插入数据库zend 1多行

1 个答案: