Question

我有一张包含以下示例数据的表格：

ID    | RecordID  | Time     | Start/End
1       1111       09:00:10          
5       1111       09:00:12    
13      1111       09:01:10   
24      1111       09:02:30          
27      9999       10:00:10          
29      9999       10:01:22   
30      9999       10:03:10          
38      7777       10:20:10          
59      7777       10:21:10   
60      7777       10:24:10          
71      1111       14:20:10          
72      1111       14:21:10   
75      1111       14:24:10

当RecordID是第一个和最后一个实例时，如何查询表以向Start/End列添加1？

ID    | RecordID  | Time     | Start/End
1       1111       09:00:10          1
5       1111       09:00:12    
13      1111       09:01:10   
24      1111       09:02:30          1
27      9999       10:00:10          1
29      9999       10:01:22   
30      9999       10:03:10          1
38      7777       10:20:10          1
59      7777       10:21:10   
60      7777       10:24:10          1
71      1111       14:20:10          1
72      1111       14:21:10   
75     1111       14:24:10          1

我是否需要遍历表格？

请注意，RecordID可以在一天内不止一次出现在表格中。

EDIT -----------------------------

Aplogies，我最初声明ID会是增量的，但事实并非如此 - 如果我为1位用户提取数据，上面的表就是这样。

Answer 1

查询：

<强> SQLFIDDLEEXample

UPDATE t
SET [Start/End] = CASE WHEN t1.ID is null or t2.ID is null
     THEN 1
     WHEN t.RecordID <> t1.RecordID OR t.RecordID <> t2.RecordID
     THEN 1 END 
FROM Table1 t
LEFT JOIN Table1 t1
  ON t1.ID = t.ID - 1
LEFT JOIN Table1 t2
  ON t2.ID = t.ID + 1

结果：

| ID | RECORDID |     TIME | START/END |
|----|----------|----------|-----------|
|  1 |     1111 | 09:00:10 |         1 |
|  2 |     1111 | 09:00:12 |    (null) |
|  3 |     1111 | 09:01:10 |    (null) |
|  4 |     1111 | 09:02:30 |         1 |
|  5 |     9999 | 10:00:10 |         1 |
|  6 |     9999 | 10:01:22 |    (null) |
|  7 |     9999 | 10:03:10 |         1 |
|  8 |     7777 | 10:20:10 |         1 |
|  9 |     7777 | 10:21:10 |    (null) |
| 10 |     7777 | 10:24:10 |         1 |
| 11 |     1111 | 14:20:10 |         1 |
| 12 |     1111 | 14:21:10 |    (null) |
| 13 |     1111 | 14:24:10 |         1 |

修改

新查询：的 SQLFIDDLEExample

;WITH CTE AS ( SELECT *, ROW_NUMBER()OVER(ORDER BY ID) rnka FROM Table1) UPDATE t SET [Start/End] = CASE WHEN t1.ID is null or t2.ID is null THEN 1 WHEN t.RecordID <> t1.RecordID OR t.RecordID <> t2.RecordID THEN 1 END FROM CTE t LEFT JOIN CTE t1 ON t1.rnka = t.rnka - 1 LEFT JOIN CTE t2 ON t2.rnka = t.rnka + 1

结果：

| ID | RECORDID | TIME | START/END | |----|----------|----------|-----------| | 1 | 1111 | 09:00:10 | 1 | | 5 | 1111 | 09:00:12 | (null) | | 13 | 1111 | 09:01:10 | (null) | | 24 | 1111 | 09:02:30 | 1 | | 27 | 9999 | 10:00:10 | 1 | | 29 | 9999 | 10:01:22 | (null) | | 30 | 9999 | 10:03:10 | 1 | | 38 | 7777 | 10:20:10 | 1 | | 59 | 7777 | 10:21:10 | (null) | | 60 | 7777 | 10:24:10 | 1 | | 71 | 1111 | 14:20:10 | 1 | | 72 | 1111 | 14:21:10 | (null) | | 75 | 1111 | 14:24:10 | 1 |

Answer 2

编辑我的回答：

好吧，您可以使用以下更新查询：

UPDATE t SET t.Start/End = 1 FROM table t INNER JOIN (SELECT MIN(Id) IdMin,MIN(Time) FROM table GROUP BY RecordId) t1 ON t.Id = t1.IdMin

UPDATE t SET t.Start/End = 1 FROM table t INNER JOIN (SELECT NAX(Id) IdMax,MAX(Time) FROM table WHERE Start/End IS NULL GROUP BY RecordId ) t1 ON t.Id = t1.IdMax

Answer 3

This will work:

;WITH CTE AS (
        SELECT t1.ID,
               CASE WHEN t1.RecordID <> ISNULL(t2.RecordID,0) THEN 1 ELSE 0 END [Start/END]
            FROM TableName t1
                LEFT JOIN TableName t2
                ON t1.ID = t2.ID + 1

        UNION ALL

        select t1.ID,
                CASE WHEN t1.RecordID <> ISNULL(t2.RecordID,0) THEN 1 ELSE 0 END [Start/END]
            FROM TableName t1
                LEFT JOIN TableName t2
                ON t1.ID = t2.ID - 1

)
UPDATE TableName
SET [Start/END] = 1
    FROM TableName t
        INNER JOIN cte
        ON t.ID = CTE.ID
    WHERE cte.[Start/END] = 1

根据另一列中的值更改来更新1列

3 个答案: