如何在textview中显示已解析的整数字符串

Question

我很难获得包含用户输入的字符串，并在单击按钮时在文本视图中显示它。例如，如果用户键入 10 并单击按钮，我希望textview显示 10 。我收到警告说 answerINT 从未使用过。

代码我遇到了

的问题

                //Fetches user answer and converts it into an integer
                EditText answer = (EditText)findViewById(R.id.editanswer); {
                if (answer.getText().toString().length() > 0){
                    int answerInt = Integer.parseInt(answer.getText().toString());

                    //Display answer in textview on click
                    TextView displayanswer = (TextView) findViewById(R.id.tvdisplayanswer);
                    displayanswer.setText(answer);

                }

其中的coode

            findViewById(R.id.btnok).setOnClickListener(new OnClickListener() {
            public void onClick(View v) {
                Log.d("onClick", "OK button was clicked");

                //Fetches user answer and converts it into an integer
                EditText answer = (EditText)findViewById(R.id.editanswer); {
                if (answer.getText().toString().length() > 0){
                    int answerInt = Integer.parseInt(answer.getText().toString());

                    //Display answer in textview on click
                    TextView displayanswer = (TextView) findViewById(R.id.tvdisplayanswer);
                    displayanswer.setText(answer);

                }
            //Displaying a toast if no answer is provided
                else
                {
                    Toast.makeText(getApplicationContext(), "No answer provided!",
                           Toast.LENGTH_SHORT).show();
                }


                    }

Answer 1

试试这个

 displayanswer.setText(" "+answerInt);

OR

displayanswer.setText(String.valueOf(answerInt));

Answer 2

试试这个：

displayanswer.setText(""+answerInt);

Answer 3

您可以使用：

String.valueOf(yourint);

Answer 4

你可以这样做：

if (answer.getText().toString().length() > 0){
                //Display answer in textview on click
                TextView displayanswer = (TextView) findViewById(R.id.tvdisplayanswer);
                displayanswer.setText(answer.getText().toString());

            }