Question

我有一个viewPager，它必须防止反击。这是我的代码

   public class testActivity extends FragmentActivity
   {
ViewPager pager;
LayoutInflater inflater;
List<String> qNum;
int id=1;
MyPagesAdapter adapter;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.test_page);

    qNum=new ArrayList<String>();
    qNum.add("1");
    qNum.add("2");
    qNum.add("3");
    qNum.add("4");
    qNum.add("5");
    System.out.println(qNum);
    inflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);

    adapter=new MyPagesAdapter();

    pager = (ViewPager) findViewById(R.id.pager);
    pager.setAdapter(adapter);

           id = pager.getCurrentItem();
           System.out.println("id returns "+id);

}


class MyPagesAdapter extends PagerAdapter {
    @Override
    public int getCount() {
        return qNum.size();
    }


    @Override
    public Object instantiateItem(ViewGroup container, int position) {

        View view = inflater.inflate(R.layout.question_model, container,false);
        System.out.println("current pos: "+position);

        ((TextView)view.findViewById(R.id.numberView)).setText(String.valueOf(qNum.get(0)));
            ((ViewPager) container).addView(view, 0);

        if(position>id)
        {
            System.out.println("removes id "+qNum.get(0));
            qNum.remove(0);
            System.out.println(qNum);
            adapter.notifyDataSetChanged();
            id=position;
            ((ViewPager) container).removeView((view));

            ((TextView)view.findViewById(R.id.numberView)).setText(String.valueOf(qNum.get(0)));

            ((ViewPager) container).addView(view, 0);

             return view;
        }
        else if(position==id)
        {
            System.out.println("position and id equals");
            ((TextView)view.findViewById(R.id.numberView)).setText(String.valueOf(qNum.get(0)));
           ((ViewPager) container).addView(view, 0);
            return view;
        }
        else if(position<id)
            return R.layout.finish;

          return R.layout.finish_test;  

    }

     @Override
    public boolean isViewFromObject(View arg0, Object arg1) {
        return arg0==(View)arg1;
    }

    @Override
    public void destroyItem(ViewGroup container, int position, Object object) {
      ((ViewPager) container).removeView((View) object);
      object=null;
    }
}

}

我的问题是LogCat在从列表中删除元素后显示正确的列表，但在模拟器中，它在2次刷卡后没有变化（我只能看到问题4，但是当我离开手指时它返回到2 ）。当我向右滑动时它也显示已移除的项目

我的LogCat是

05-09 02:02:58.561: I/System.out(2252): [1, 2, 3, 4, 5]
05-09 02:02:58.621: I/System.out(2252): id returns 0
05-09 02:03:01.161: I/System.out(2252): current pos: 0
05-09 02:03:01.171: I/System.out(2252): position and id equals
05-09 02:03:01.361: I/System.out(2252): current pos: 1
05-09 02:03:01.391: I/System.out(2252): removes id 1
05-09 02:03:01.391: I/System.out(2252): [2, 3, 4, 5]
05-09 02:03:28.101: I/System.out(2252): current pos: 2
05-09 02:03:28.141: I/System.out(2252): removes id 2
05-09 02:03:28.151: I/System.out(2252): [3, 4, 5]
05-09 02:03:28.351: I/System.out(2252): current pos: 2
05-09 02:03:28.381: I/System.out(2252): removes id 3
05-09 02:03:28.381: I/System.out(2252): [4, 5]

Answer 1

您可以从下面的文档中获得一个很好的参考，即使它们是一个可以帮助您的示例项目。

http://architects.dzone.com/articles/android-tutorial-using

ViewPager不会更改其内容

1 个答案: