假设我有一个结构:
struct Game
{
int id;
int year;
string title;
string publisher;
string developer;
};
现在我有一个.txt文件,其内容如下:
1 2012 FarCry Crytek Ubisoft
现在,当我运行程序时,我希望程序能够使用新的矢量Game,并根据外部.txt文件中该行中的数据设置其值。这可以实现吗?任何帮助,将不胜感激。 到目前为止,这是我的代码:
#include "stdafx.h"
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
using namespace std;
struct Game
{
int id;
int year;
string title;
string publisher;
string developer;
};
void ShowData(vector<Game> myDatabase)
{
cout << endl;
for(size_t i = 0; i <= myDatabase.size()-1; i++)
{
cout << endl;
cout << "ITEM NO" << "[" << i + 1 << "]" <<endl;
cout << " TITLE: " << myDatabase[i].title << endl;
cout << " YEAR: " << myDatabase[i].year << endl;
cout << "DEVELOPER: " << myDatabase[i].developer << endl;
cout << "PUBLISHER: " << myDatabase[i].publisher << endl;
}
}
int _tmain(int argc, _TCHAR* argv[])
{
string option;
int serialNumber = 0;
int count = 0;
char str[80];
vector<Game> Database;
fstream fout;
fout.open("Database.txt");
cout << endl;
repeat:
cout << endl;
cout << "ADD | SHOW | DELETE | EDIT | SEARCH " << endl;
cout << "SAY : ";
cin >> option;
if(option == "ADD" || option == "Add" || option == "add")
{
serialNumber += 1;
Game NewGame;
NewGame.id = serialNumber;
cout << endl << "Name: ";
cin >> NewGame.title;
cout << "Year: ";
cin >> NewGame.year;
cout << "Developer: ";
cin >> NewGame.developer;
cout << "Publisher: ";
cin >> NewGame.publisher;
cout << endl;
Database.push_back(NewGame);
cout << endl;
cout << "Size is: " << Database.size();
fout << serialNumber << " " << Database[Database.size() - 1].title << " " << Database[Database.size() - 1].year << " "<< Database[Database.size() - 1].developer << " " << Database[Database.size() - 1].publisher << endl;
goto repeat;
}
if (option == "SHOW" || option == "Show" || option == "show")
{
ShowData(Database);
goto repeat;
}
if(option == "DELETE" || option == "Delete" || option == "delete")
{
int choose;
cout << "Delete Item No: ";
cin >> choose;
Database.erase(Database.begin() + (choose - 1));
cout << endl;
ShowData(Database);
goto repeat;
}
if(option == "SEARCH" || option == "Search" || option == "search")
{
cout << "Search By [ID, TITLE, YEAR, DEVELOPER, PUBLISHER] : ";
string choose;
cin >> choose;
if(choose == "ID" || choose == "Id" || choose == "id")
{
int idNumber;
cout << "ID No: ";
cin >> idNumber;
cout << endl;
cout << "ITEM NO" << "[" << idNumber << "]" <<endl;
cout << " TITLE: " << Database[idNumber - 1].title << endl;
cout << " YEAR: " << Database[idNumber - 1].year << endl;
cout << "DEVELOPER: " << Database[idNumber - 1].developer << endl;
cout << "PUBLISHER: " << Database[idNumber - 1].publisher << endl;
goto repeat;
}
else if (choose == "TITLE" || choose == "Title" || choose == "title")
{
string whatTitle;
cout << "Enter Title: ";
cin >> whatTitle;
for(size_t i = 0; i <= Database.size()-1; i++)
{
if(Database[i].title == whatTitle)
{
cout << endl;
cout << "ITEM NO" << "[" << i + 1 << "]" <<endl;
cout << " TITLE: " << Database[i].title << endl;
cout << " YEAR: " << Database[i].year << endl;
cout << "DEVELOPER: " << Database[i].developer << endl;
cout << "PUBLISHER: " << Database[i].publisher << endl;
}
}
goto repeat;
}
else if (choose == "YEAR" || choose == "Year" || choose == "year")
{
int whatYear;
cout << "Enter Year: ";
cin >> whatYear;
for(size_t i = 0; i <= Database.size()-1; i++)
{
if(Database[i].year == whatYear)
{
cout << endl;
cout << "ITEM NO" << "[" << i + 1 << "]" <<endl;
cout << " TITLE: " << Database[i].title << endl;
cout << " YEAR: " << Database[i].year << endl;
cout << "DEVELOPER: " << Database[i].developer << endl;
cout << "PUBLISHER: " << Database[i].publisher << endl;
}
}
goto repeat;
}
else if (choose == "DEVELOPER" || choose == "Developer" || choose == "developer")
{
string whatDeveloper;
cout << "Enter Developer Name: ";
cin >> whatDeveloper;
for(size_t i = 0; i <= Database.size()-1; i++)
{
if(Database[i].developer == whatDeveloper)
{
cout << endl;
cout << "ITEM NO" << "[" << i + 1 << "]" <<endl;
cout << " TITLE: " << Database[i].title << endl;
cout << " YEAR: " << Database[i].year << endl;
cout << "DEVELOPER: " << Database[i].developer << endl;
cout << "PUBLISHER: " << Database[i].publisher << endl;
}
}
goto repeat;
}
else if (choose == "PUBLISHER" || choose == "Publisher" || choose == "publisher")
{
string whatPublisher;
cout << "Enter Publisher Name: ";
cin >> whatPublisher;
for(size_t i = 0; i <= Database.size()-1; i++)
{
if(Database[i].publisher == whatPublisher)
{
cout << endl;
cout << "ITEM NO" << "[" << i + 1 << "]" <<endl;
cout << " TITLE: " << Database[i].title << endl;
cout << " YEAR: " << Database[i].year << endl;
cout << "DEVELOPER: " << Database[i].developer << endl;
cout << "PUBLISHER: " << Database[i].publisher << endl;
}
}
goto repeat;
}
}
if (option == "EDIT" || option == "Edit" || option == "edit")
{
int whichItem;
cout << "Enter Item No: ";
cin >> whichItem;
cout << endl << "Name: ";
string name;
cin >> name;
Database[whichItem - 1].title = name;
cout << "Year: ";
int year;
cin >> year;
Database[whichItem - 1].year = year;
cout << "Developer: ";
string developer;
cin >> developer;
Database[whichItem - 1].developer = developer;
cout << "Publisher: ";
string publisher;
cin >> publisher;
Database[whichItem - 1].publisher = publisher;
cout << endl;
ShowData(Database);
goto repeat;
}
fout.close();
system("PAUSE");
return 0;
}
我要做的是,当我运行程序时,它应该从文本文件中获取所有数据并将它们放在它们的相对结构中,然后将每个结构推送到一个向量中。
答案 0 :(得分:2)
解决方案1
space
字符拆分字符串作为分隔符here是一个示例解决方案2
如果每行中有相同数量的令牌(此处为5),则每个令牌都可以单独读取
std::ifstream file(fileName);
struct Game game;
file >> game.id >> game.year>>game.title>>game.publisher>>game.developer;