Question

Cell_in = {'a1','b1','b3','c3','c1','d3'};  % something like this

Cell_out = {'a1','b1','c1'; 
       'b3','c3','d3';...
       }

等等，怎么办呢？

Answer 1

案例1：一致的尺寸

%%// Input (different from question for a better demo)
Cell_in = {'airplane1','bat1','ball3','cat3','coal1','doggie3'};

ids = cellfun(@(x) x(end), Cell_in,'uni',0) 
[~,ind] = sort(ids)
Cell_out = reshape(Cell_in(ind),[],numel(unique(ids)))' %%// Output

<强>输出

Cell_out = 

    'airplane1'    'bat1'    'coal1'  
    'ball3'        'cat3'    'doggie3'

案例2：不一致的尺寸

Cell_in = {'airplane1','bat1','ball3','cat3','coal1','doggie3','cat2','ball2'};

ids = cellfun(@(x) x(end), Cell_in,'uni',0)
unique_ids_num = cellfun(@str2num,unique(ids))
ids_num = cellfun(@str2num,ids)

counts = histc(ids_num,sort(unique_ids_num))

Cell_out = cell(numel(unique_ids_num),max(counts));
for k =1:numel(counts) %%// Maybe accumarray can work here
    Cell_out(k,1:counts(k)) = Cell_in(ids_num==unique_ids_num(k));
end

<强>输出

Cell_out = 

    'airplane1'    'bat1'     'coal1'  
    'cat2'         'ball2'           []
    'ball3'        'cat3'     'doggie3'

Answer 2

按照kyamagu的建议使用regexp，然后accumarray进行分组：

[~,~,ic] = unique(cell2mat(regexp(Cell_in(:), '\d+$', 'match', 'once')));
[ic,inds] = sort(ic); % to ensure stable ordering of output
co = accumarray(ic,inds,[],@(x){Cell_in(x)});
Cell_out = vertcat(co{:});

单独的字符串并从单元格数组中创建一个组

2 个答案: