Question

我有以下方案：

我需要计算有多少客户的未付款状态。并且此计数必须仅显示具有计数>= 2的计数。这部分我正确地做（我认为）：

--SELECTING Client Count
SELECT Client, COUNT(HyphenStatus) as UnpaidCount
FROM CasesFromSimplicity
WHERE HyphenStatus = 'UnPaid' AND FCManager = 'Mike'
GROUP BY Client
HAVING COUNT(HyphenStatus) >= 2
ORDER BY Client ASC

然后我需要为经理视图创建一个看起来像这样的表：

+-----------+--------------+----------------+------------+
| FCManager | CountingTwos | CountingThrees | FourOrMore |
+-----------+--------------+----------------+------------+
| Mike      |            2 |              1 |          1 |
+-----------+--------------+----------------+------------+

这告诉我，我的顾问Mike有两个客户，其中包含count of 2和one client with a count of 3以及one client with a count of 4。

我此刻已经做了以下查询，但这似乎没有起作用。

--Selecting the count for manager
SELECT
FCManager
,(SELECT COUNT(HyphenStatus) FROM CasesFromSimplicity WHERE HyphenStatus = 'UnPaid' AND FCManager = 'Mike' HAVING COUNT(HyphenStatus) = 2) CountingTwos
,(SELECT COUNT(HyphenStatus) FROM CasesFromSimplicity WHERE HyphenStatus = 'UnPaid' AND FCManager = 'Mike' HAVING COUNT(HyphenStatus) = 3) CountingThrees
,(SELECT COUNT(HyphenStatus) FROM CasesFromSimplicity WHERE HyphenStatus = 'UnPaid' AND FCManager = 'Mike' HAVING COUNT(HyphenStatus) >= 4) FourOrMore
FROM CasesFromSimplicity
GROUP BY FCManager

有谁能告诉我我做错了什么？或者把我送到正确的地方阅读。我在搜索时找不到任何东西。 我在发帖时一直在想，我会在子查询中需要一个组，但是这会返回多于1个结果而不起作用？

我为您创建了一个SQL Fiddle来查看我的问题。

感谢Mike，感谢任何帮助。

如果我需要进一步解释，请告诉我？我正在使用SQL SERVER 2008

Answer 1

好吧，假设SQL Server 2005+，你可以这样做：

;WITH CTE AS
(
    SELECT  FCManager,
            Client, 
            COUNT(HyphenStatus) as UnpaidCount
    FROM CasesFromSimplicity
    WHERE HyphenStatus = 'UnPaid' 
    GROUP BY FCManager,
             Client
    HAVING COUNT(HyphenStatus) >= 2
)
SELECT  FCManager,
        SUM(CASE WHEN UnpaidCount = 2 THEN 1 ELSE 0 END) CountingTwos,
        SUM(CASE WHEN UnpaidCount = 3 THEN 1 ELSE 0 END) CountingThrees,
        SUM(CASE WHEN UnpaidCount > 3 THEN 1 ELSE 0 END) FourOrMore 
FROM CTE 
GROUP BY FCManager

Here is修改后的sqlfiddle。

SQL计数麻烦

1 个答案: