我有这样的代码
<ListBox x:Name="filterListBox" Height="60">
<ListBox.ItemsPanel>
<ItemsPanelTemplate>
<StackPanel Orientation="Horizontal"
VirtualizingStackPanel.VirtualizationMode="Standard"/>
</ItemsPanelTemplate>
</ListBox.ItemsPanel>
<ListBox.ItemTemplate>
<DataTemplate>
<StackPanel x:Name="TargetPanel">
</StackPanel>
</DataTemplate>
</ListBox.ItemTemplate>
<ListBox.Background>
<SolidColorBrush />
</ListBox.Background>
</ListBox>
我得到第一个列表框项目
object item = filterListBox.ItemContainerGenerator.ContainerFromIndex(0);
ListBoxItem lbi = item as ListBoxItem;
现在我需要将这个堆栈面板称为&#34; TargetPanel&#34;但我不知道怎么做。你能帮忙吗?
答案 0 :(得分:0)
遗憾的是,没有一种内置方法可以通过简单的方法调用来实现。但是,这很容易。通过对this示例进行一些修改,您可以通过name
获取DataTemplate的特定子项:
// the call
var item = filterListBox.ItemContainerGenerator
.ContainerFromIndex(0) as ListBoxItem;
var sp = FindVisualChild<StackPanel>(item, "TargetPanel");
// the variable sp should be set to the TargetPanel for the item now
你需要在某处添加的代码(它可能在“帮助者”类中):
using System.Windows.Media; // for VisualTreeHelper
private static TChildItem FindVisualChild<TChildItem>(DependencyObject obj,
string matchName = "") where TChildItem : DependencyObject
{
for (int i = 0; i < VisualTreeHelper.GetChildrenCount(obj); i++)
{
var child = VisualTreeHelper.GetChild(obj, i);
if (child != null && child is TChildItem)
{
// match by name
var childName = child.GetValue(FrameworkElement.NameProperty) as string;
if (!string.IsNullOrWhiteSpace(matchName))
{
if (matchName == childName)
{
return (TChildItem)child;
}
}
else
{
return (TChildItem)child;
}
}
else
{
var childOfChild = FindVisualChild<TChildItem>(child, matchName);
if (childOfChild != null)
{
return childOfChild;
}
}
}
return null;
}