Question

我想将此代码输出到php页面。

SET group_concat_max_len=5000;  
SET @sql = NULL;    

SELECT GROUP_CONCAT(DISTINCT CONCAT('MAX(IF(date = ''', date, ''', present, NULL)) AS ''',date, '''')) 
INTO @sql
FROM tblattendanceregister;

SET @sql = CONCAT('SELECT employee, ', @sql, ' 
                    FROM tblattendanceregister 
                    GROUP BY employee');

PREPARE stmt FROM @sql;
EXECUTE stmt;

到目前为止我已尝试过这个：

<table border="0" name="attReportTable" id="attReportTable" class="table table-striped table-header-rotated">

<?php
$dySet=mysql_query("SET group_concat_max_len=5000;
    SET @sql = NULL;
    SELECT
      GROUP_CONCAT(DISTINCT
        CONCAT(
          'MAX(IF(date = ''',
          date,
          ''', present, NULL)) AS ''',date, ''''
        )
      ) INTO @sql
    FROM tblattendanceregister;

SET @sql = CONCAT('SELECT employee, ', @sql, ' FROM tblattendanceregister GROUP BY  employee');
                                                PREPARE stmt FROM @sql;
EXECUTE stmt;");

while($dy=mysql_fetch_array($dySet)){

?>
<tr>
<td align="center" valign="middle"><div><?php echo $dy["employee"];?></div></td>
<td class="rotate-45"><div><span><?php echo date('d-M',strtotime($dy["date"]));?></span></div></td>
</tr>
<?php 
}

?>
</table>

我一直收到这个错误：

警告：mysql_fetch_array（）要求参数1为资源，布尔值在第729行的C：\ wamp \ www \ cbmwdb \ systemfiles \ supchain \ PersonnelPerformance.php中给出。

第729行是while循环开始的地方。

在php中生成交叉表查询

0 个答案: