Question

我正在尝试将视频文件上传到服务器并转换为base64。但我的内存异常甚至大小也是2 mb。如何解决此问题。请帮我过来，非常感谢你的帮助。

这就是我在做什么

  byte [] ba = convertByteArray(videoUri);
String baseimage=Base64.encodeToString(ba, Base64.NO_WRAP);

 public byte[] convertByteArray(Uri videoUri){

         InputStream iStream=null;
         byte[] inputData=null;
        try {
            iStream = getContentResolver().openInputStream(videoUri);
            inputData = getBytes(iStream);

        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }
        catch (IOException e) {
            e.printStackTrace();
        }


        return inputData;
     }

     public byte[] getBytes(InputStream inputStream) throws IOException {
          ByteArrayOutputStream byteBuffer = new ByteArrayOutputStream();
          int bufferSize = 1024;
          byte[] buffer = new byte[bufferSize];

          int len = 0;
          while ((len = inputStream.read(buffer)) != -1) {
            byteBuffer.write(buffer, 0, len);
          }
          return byteBuffer.toByteArray();
        }

Answer 1

代码：

    HttpURLConnection conn = null;
    DataOutputStream dos = null;
    DataInputStream inStream = null;
    String lineEnd = "rn";
    String twoHyphens = "--";
    String boundary =  "*****";
    int bytesRead, bytesAvailable, bufferSize;
    byte[] buffer;
    int maxBufferSize = 1*1024*1024;
    String responseFromServer = "";
    String urlString = "http://your_website.com/upload_audio_test/upload_audio.php";
    try
    {
     //------------------ CLIENT REQUEST
    FileInputStream fileInputStream = new FileInputStream(new File(selectedPath) );
     // open a URL connection to the Servlet
     URL url = new URL(urlString);
     // Open a HTTP connection to the URL
     conn = (HttpURLConnection) url.openConnection();
     // Allow Inputs
     conn.setDoInput(true);
     // Allow Outputs
     conn.setDoOutput(true);
     // Don't use a cached copy.
     conn.setUseCaches(false);
     // Use a post method.
     conn.setRequestMethod("POST");
     conn.setRequestProperty("Connection", "Keep-Alive");
     conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
     dos = new DataOutputStream( conn.getOutputStream() );
     dos.writeBytes(twoHyphens + boundary + lineEnd);
     dos.writeBytes("Content-Disposition: form-data; name="uploadedfile";filename="" + selectedPath + """ + lineEnd);
     dos.writeBytes(lineEnd);
     // create a buffer of maximum size
     bytesAvailable = fileInputStream.available();
     bufferSize = Math.min(bytesAvailable, maxBufferSize);
     buffer = new byte[bufferSize];
     // read file and write it into form...
     bytesRead = fileInputStream.read(buffer, 0, bufferSize);
     while (bytesRead > 0)
     {
      dos.write(buffer, 0, bufferSize);
      bytesAvailable = fileInputStream.available();
      bufferSize = Math.min(bytesAvailable, maxBufferSize);
      bytesRead = fileInputStream.read(buffer, 0, bufferSize);
     }
     // send multipart form data necesssary after file data...
     dos.writeBytes(lineEnd);
     dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
     // close streams
     Log.e("Debug","File is written");
     fileInputStream.close();
     dos.flush();
     dos.close();
    }
    catch (MalformedURLException ex)
    {
         Log.e("Debug", "error: " + ex.getMessage(), ex);
    }
    catch (IOException ioe)
    {
         Log.e("Debug", "error: " + ioe.getMessage(), ioe);
    }
    //------------------ read the SERVER RESPONSE
    try {
          inStream = new DataInputStream ( conn.getInputStream() );
          String str;

          while (( str = inStream.readLine()) != null)
          {
               Log.e("Debug","Server Response "+str);
          }
          inStream.close();

    }
    catch (IOException ioex){
         Log.e("Debug", "error: " + ioex.getMessage(), ioex);
    }
  }

浏览以下示例以获取更多参考：

http://coderzheaven.com/2011/08/uploading-audio-video-or-image-files-from-android-to-server/

要将视频上传到服务器，请参阅上面的URL中的doFileUpload（）方法。

编码到base64视频文件时出现内存不足问题

1 个答案: