匹配$ {123 ... 456}并在Java中提取2个数字?

时间:2014-05-08 09:39:27

标签: java regex

当我知道格式始终为${INT1...INT2}时,从String中预期2个整数的最简单方法是什么? “Hello ${123...456}会提取123,456

2 个答案:

答案 0 :(得分:4)

我会选择Pattern组和反向引用。

以下是一个例子:

String input = "Hello ${123...456}, bye ${789...101112}";
//                           | escaped "$"
//                           |  | escaped "{"
//                           |  |  | first group (any number of digits)
//                           |  |  |    | 3 escaped dots
//                           |  |  |    |       | second group (same as 1st)
//                           |  |  |    |       |    | escaped "}"
Pattern p = Pattern.compile("\\$\\{(\\d+)\\.{3}(\\d+)\\}");
Matcher m = p.matcher(input);
// iterating over matcher's find for multiple matches
while (m.find()) {
    System.out.println("Found...");
    System.out.println("\t" + m.group(1));
    System.out.println("\t" + m.group(2));
}

<强>输出

Found...
    123
    456
Found...
    789
    101112

答案 1 :(得分:0)

final String string = "${123...456}";
final String firstPart = string.substring(string.indexOf("${") + "${".length(), string.indexOf("..."));
final String secondPart = string.substring(string.indexOf("...") + "...".length(), string.indexOf("}"));
final Integer integer = Integer.valueOf(firstPart.concat(secondPart));