Question

所以我对以下内容感到有些困惑。我有两个表，项目和变化。

项目：

- id
- title
- description
- datecreated

变化：

- id
- title
- description
- projectid FOREIGN KEY
- datecreated

我无法弄清楚如何

insert into change (name, description, projectid) value (:name, :description, :projectid)
select id from project
where name = $name

重要 - 插入中的名称和描述由php变量使用表单提供。

重要 - 必须使用PDO

实际代码：

$sql = "INSERT INTO change (title, description, project_id) SELECT :title, :description, id FROM project WHERE title = :project_title";
$query = $db->prepare($sql);
$query->execute(array(":title" => $title, ":description" => $description, ":project_title" => $created));

这就是我最后所做的事情，但Barmar在这个和另一个问题上得到了帮助。

   $sql = "INSERT INTO `change` (`title`, `description`, `project_id`) SELECT :title, :description, id FROM project WHERE title = :project_title";
$query = $db->prepare($sql);
$query->execute(array(":title" => $title, ":description" => $description, ":project_title" => $created));

Answer 1

插入时，您可以使用values子句，也可以使用select指定数据源。你不能同时使用它们。

你想：

INSERT INTO `change` (`title`, `description`, `projectid`)
SELECT :title, :description, id
FROM project
WHERE title = :project_title

php，pdo mysql不能插入内连接

1 个答案: