如何按键值合并两个Javascript对象

时间:2014-05-08 06:15:41

标签: javascript jquery

我需要通过其键值映射合并两个Javascript对象。

这是我的第一个Javascript对象

var json1= [
    { ID: 1, limit: 5, name: "foo" }, 
    { ID: 2, limit: 9, name: "dog" }

   ];

这是我的第二个Javascript对象

 var json2 = [
        { ID: 2, validate: false, LastRunTime: "February" }, 
        { ID: 1, validate: true, LastRunTime: "January" }
    ];
 $.extend(true, {}, json1, json2);

这给了我这样的Javascript

[
    {
        {
            ID: 2,
            LastRunTime: "February",
            limit: 5,
            name: "foo",
            validate: false
        },
        {
            ID: 1,
            LastRunTime: "January",
            limit: 9,
            name: "dog",
            validate: true
        }
    }
]

但是我正在寻找将ID映射为键的代码,然后合并这样的Javascript对象而不管它们在数组中的顺序。

[
    {
        {
            ID: 1,
            LastRunTime: "January",
            limit: 5,
            name: "foo",
            validate: true
        },
        {
            ID: 2,
            LastRunTime: "February",
            limit: 9,
            name: "dog",
            validate: false
        }
    }
]

2 个答案:

答案 0 :(得分:2)

您需要切换数据表示。最好的方法是将你的json存储为:

var json1 = {
    "1": { ID: 1, limit: 5, name: "foo" }, 
    "2": { ID: 2, limit: 9, name: "dog" }
};

如果不可能,那么您可以动态转换数据:

var json1obj = {};
json1.forEach(function(obj) {
  json1obj[obj.ID] = obj;
});
var json2obj = ...;

$.extend(true, {}, json1obj, json2obj);

答案 1 :(得分:0)

var result = [];
for (var i = 0; i < json1.length; i++) {
    var found = false;
    for (var j = 0; j < json2.length; j++) {
        if (json1[i].ID == json2[j].ID) {
            result.push($.extend(true, {}, json1[i], json2[j]));
            found = true;
            break;
        }
    }
    if (!found) {
        // If no match found in json2, put a copy in the result
        result.push($.extend(true, {}, json1[i]));
    }
}