Web.xml中的错误“元素 - 此处不允许

时间:2014-05-07 13:49:17

标签: java xml spring spring-mvc web.xml

大家好我的Web.xml中有问题。我在这里不允许使用以下错误元素。这是我的Web.xml

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
            http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

    <display-name>Spring MVC Application</display-name>

    <description>MySQL Test App</description>
    <resource-ref>
        <description>DB Connection</description>
        <res-ref-name>jdbc/mobile</res-ref-name>
        <res-type>javax.sql.DataSource</res-type>
        <res-auth>Container</res-auth>
    </resource-ref>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            /WEB-INF/spring-config.xml
        </param-value>
    </context-param>

    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>

    <filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring-config.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

    <welcome-file-list>
        <welcome-file>login.jsp</welcome-file>
    </welcome-file-list>

</web-app>

我在这一行得到错误。

<resource-ref>
    <description>DB Connection</description>
    <res-ref-name>jdbc/mobile</res-ref-name>
    <res-type>javax.sql.DataSource</res-type>
    <res-auth>Container</res-auth>
</resource-ref>

并且在这一行。

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

并非全部,每当我启动项目时(使用tomcat8),我都不会遇到任何编译错误。我的Web应用程序启动就像正常一样。我在这里做错了什么?

0 个答案:

没有答案