Question

我过去曾经读过，嵌套多种资源并不是一种好的做法。

我有模特，酒店，房间和参观。（H has_many R，R有很多V）

如果你不应该多次筑巢，如下面......

  resources :hotels do
    resources :rooms do
      resources :visits
    end
  end

那么最佳做法是什么？

我希望能够通过房间/ 3 /访问等方式检索特定房间的所有访问...但我目前无法做到这一点，因为上述代码会破坏最佳实践嵌套。

Answer 1

浅嵌套

“避免深度嵌套的一种方法（如上所述）是生成在父级下作用域的集合操作，以便了解层次结构，但不嵌套成员操作。”

See Rails Guide on Routing Section 2.7.2 Shallow Nesting for more information

在你的情况下，你会看到：

resources :hotels do
  resources :rooms, shallow: true
end

resources :rooms, only: [] do
    resources :visits
end

这相当于：

resources :hotels do
  resources :rooms, only: [:index, :new, :create]
end
resources :rooms, only: [:show, :edit, :update, :destroy]

并将为您提供以下路线：

                 GET    /hotels/:hotel_id/rooms(.:format)            rooms#index
                 POST   /hotels/:hotel_id/rooms(.:format)            rooms#create
  new_hotel_room GET    /hotels/:hotel_id/rooms/new(.:format)        rooms#new
       edit_room GET    /rooms/:id/edit(.:format)                    rooms#edit
            room GET    /rooms/:id(.:format)                         rooms#show
                 PATCH  /rooms/:id(.:format)                         rooms#update
                 PUT    /rooms/:id(.:format)                         rooms#update
                 DELETE /rooms/:id(.:format)                         rooms#destroy
          hotels GET    /hotels(.:format)                            hotels#index
                 POST   /hotels(.:format)                            hotels#create
       new_hotel GET    /hotels/new(.:format)                        hotels#new
      edit_hotel GET    /hotels/:id/edit(.:format)                   hotels#edit
           hotel GET    /hotels/:id(.:format)                        hotels#show
                 PATCH  /hotels/:id(.:format)                        hotels#update
                 PUT    /hotels/:id(.:format)                        hotels#update
                 DELETE /hotels/:id(.:format)                        hotels#destroy
     room_visits GET    /rooms/:room_id/visits(.:format)             visits#index
                 POST   /rooms/:room_id/visits(.:format)             visits#create
  new_room_visit GET    /rooms/:room_id/visits/new(.:format)         visits#new
 edit_room_visit GET    /rooms/:room_id/visits/:id/edit(.:format)    visits#edit
      room_visit GET    /rooms/:room_id/visits/:id(.:format)         visits#show
                 PATCH  /rooms/:room_id/visits/:id(.:format)         visits#update
                 PUT    /rooms/:room_id/visits/:id(.:format)         visits#update
                 DELETE /rooms/:room_id/visits/:id(.:format)         visits#destroy

我已经读过不要超过2的资源。如何嵌套我的酒店/房间/访问模型？

1 个答案: