ExpandableListView从View（子）获取组位置的父级

Question

我正在寻找好几个小时并且试图理解为什么当我按下孩子时没有调用“onChildClick”事件。 顺便说一句，“IsChildSelectable”在适配器中是“真实的”。

这是我的代码：

公共类Graphic_Planner扩展了Activity {

ExpandableListAdapter listAdapter;
ExpandableListView expListView;
List<String> listDataHeader;
HashMap<String, List<String>> listDataChild;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_graphic__planner);

    // get the listview
    expListView = (ExpandableListView) findViewById(R.id.lvExp);

    // preparing list data
    prepareListData();

    listAdapter = new ExpandableListAdapter(this, listDataHeader,
            listDataChild);

    // setting list adapter
    expListView.setAdapter(listAdapter);

    expListView.setOnChildClickListener(new OnChildClickListener() {
          @Override
        public boolean onChildClick(ExpandableListView parent, View v,
                int groupPosition, int childPosition, long id) {
            // TODO Auto-generated method stub
            Toast.makeText(
                    getApplicationContext(),
                    listDataHeader.get(groupPosition)
                            + " : "
                            + listDataChild.get(
                                    listDataHeader.get(groupPosition)).get(
                                    childPosition), Toast.LENGTH_SHORT)
                    .show();
            return false;
        }
    });