Question

我正在尝试绑定＆＃34;搜索栏和搜索显示控制器＆＃34;在我的UITableView中。过滤的数组具有正确的数据，但它不会在tableview中显示。当我在搜索栏中输入内容时，它会显示空白表格视图。在函数＆＃34; cellForRowAtIndexPath＆＃34;当它绑定正确的数据但仍然没有显示。在同一个功能中，我也改变了代码 UITableViewCell * cell = [tableView dequeueReusableCellWithIdentifier：@＆＃34; PersonCell＆＃34; forIndexPath：indexPath];
到 UITableViewCell * cell = [self.personTableView dequeueReusableCellWithIdentifier：@＆＃34; PersonCell＆＃34; forIndexPath：indexPath];

然后抛出以下异常：由于未捕获的异常终止应用程序＆＃39; NSInvalidArgumentException＆＃39;，原因：＆＃39; - [人员长度]：无法识别的选择器发送到实例0x1780ca170＆＃39;

代码：

-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
 if (tableView == self.searchDisplayController.searchResultsTableView) {
    return [self.filteredPersonArray count];
 } else {
    return [self.personArray count];
}
}

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
// Return the number of sections.
return 1;
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"PersonCell" forIndexPath:indexPath];

Person *person;
if (tableView == self.searchDisplayController.searchResultsTableView) {
    person = (Person *)[self.filteredPersonArray objectAtIndex:indexPath.row];
} else {
     person = (Person *)[self.personArray objectAtIndex:indexPath.row];
}
UILabel *nameLabel = (UILabel *)[cell viewWithTag:1];
nameLabel.text = [NSString stringWithFormat:@"%@ %@", person.firstName, person.lastName];
// so on;
return cell;
}

-(void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope {
// Update the filtered array based on the search text and scope.
// Remove all objects from the filtered search array
[self.filteredPersonArray removeAllObjects];
// Filter the array using NSPredicate
NSPredicate *lastNamepredicate = [NSPredicate predicateWithFormat:@"SELF.lastName contains[c] %@",searchText];
//NSPredicate *firstNamePredicate = [NSPredicate predicateWithFormat:@"SELF.firstName contains[c] %@",scope];
//tempArray = [tempArray filteredArrayUsingPredicate:lastNamepredicate];
self.filteredPersonArray = [NSMutableArray arrayWithArray:[self.personArray  
filteredArrayUsingPredicate:lastNamepredicate]];
}

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller 
shouldReloadTableForSearchString:(NSString *)searchString {
// Tells the table data source to reload when text changes
[self filterContentForSearchText:searchString scope:
 [[self.searchDisplayController.searchBar scopeButtonTitles] objectAtIndex:  
[self.searchDisplayController.searchBar selectedScopeButtonIndex]]];
// Return YES to cause the search result table view to be reloaded.
return YES;
}

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller 
shouldReloadTableForSearchScope:(NSInteger)searchOption {
// Tells the table data source to reload when scope bar selection changes
[self filterContentForSearchText:self.searchDisplayController.searchBar.text scope:
 [[self.searchDisplayController.searchBar scopeButtonTitles] objectAtIndex:searchOption]];
// Return YES to cause the search result table view to be reloaded.
return YES;
}

Answer 1

解决这个问题：
在as的情况下创建单元格时，我引用了不同的tableview对象 1.搜索后加载数据
2.在tableview中加载数据

- (UITableViewCell *)tableView:(UITableView *)tableView     cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    UITableViewCell *cell;
    Person *person;
    if (tableView == self.searchDisplayController.searchResultsTableView) 
    {
        cell = [self.personTableView dequeueReusableCellWithIdentifier:@"PersonCell"];
        person = (Person *)[self.filteredPersonArray objectAtIndex:indexPath.row];
    } else {
        cell = [tableView dequeueReusableCellWithIdentifier:@"PersonCell"];
        person = (Person *)[self.personArray objectAtIndex:indexPath.row];
    }
    UILabel *nameLabel = (UILabel *)[cell viewWithTag:1];
    nameLabel.text = [NSString stringWithFormat:@"%@ %@", person.firstName,     person.lastName];
    // so on;
    return cell;
}

过滤的数据不会显示在我的UITableView Objective C iOS7中

1 个答案: